A plant manager is concerned her equipment may need recalibrating. It seems that the actual weight of the 19 oz cereal boxes it fills has been fluctuating. The equipment needs to be recalibrated if the standard deviation exceeds 0.7 oz. In order to determine if the machine needs to be recalibrated, 71 randomly selected boes of cereal from the next day's production were weighted. the standard deviation of the 71 boxes was 0.78. Using a = 0.1, determine if the machine needs to be recalibrated. Ho:o? = H:o (Select an answer df = x² P-value = The p-value is... greater than a less than (or equal to) a

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### Determining the Need for Recalibrating Cereal Box Filling Equipment

A plant manager is concerned that her equipment may need recalibrating due to fluctuations in the actual weight of the 19 oz cereal boxes it fills. The equipment requires recalibration if the standard deviation exceeds 0.7 oz. To determine if recalibration is needed, 71 randomly selected boxes of cereal from the next day's production were weighed. The standard deviation of these boxes was found to be 0.78. Using a significance level (α) of 0.1, we need to determine if the equipment requires recalibration.

### Statistical Hypotheses
- Null Hypothesis (\(H_0\)): \(\sigma^2 =\)
- Alternative Hypothesis (\(H_a\)): \(\sigma^2\) (choose appropriate comparison) 0.49 (since \(0.7^2 = 0.49\))

### Calculation Details
- Degrees of Freedom (df) = 
- Chi-square Statistic (\(\chi^2\)) = 
- P-value = 

### P-value Comparison
The p-value is:
- [ ] greater than \(\alpha\)
- [ ] less than (or equal to) \(\alpha\)

### Decision Based on Test Statistic
This test statistic leads to a decision to:
- [ ] fail to reject the null
- [ ] accept the null
- [ ] accept the alternative
- [ ] reject the null

### Conclusion
As such, the final conclusion is that there is [ ] sufficient evidence to conclude the standard deviation in cereal box weight is [ ] than [ ].

### Graphs / Diagrams Explanation
If there are any graphs or diagrams, explain them in detail (none provided in the given image).

For further information or questions about this topic, please refer to our detailed resources on hypothesis testing and standard deviation analysis.
Transcribed Image Text:### Determining the Need for Recalibrating Cereal Box Filling Equipment A plant manager is concerned that her equipment may need recalibrating due to fluctuations in the actual weight of the 19 oz cereal boxes it fills. The equipment requires recalibration if the standard deviation exceeds 0.7 oz. To determine if recalibration is needed, 71 randomly selected boxes of cereal from the next day's production were weighed. The standard deviation of these boxes was found to be 0.78. Using a significance level (α) of 0.1, we need to determine if the equipment requires recalibration. ### Statistical Hypotheses - Null Hypothesis (\(H_0\)): \(\sigma^2 =\) - Alternative Hypothesis (\(H_a\)): \(\sigma^2\) (choose appropriate comparison) 0.49 (since \(0.7^2 = 0.49\)) ### Calculation Details - Degrees of Freedom (df) = - Chi-square Statistic (\(\chi^2\)) = - P-value = ### P-value Comparison The p-value is: - [ ] greater than \(\alpha\) - [ ] less than (or equal to) \(\alpha\) ### Decision Based on Test Statistic This test statistic leads to a decision to: - [ ] fail to reject the null - [ ] accept the null - [ ] accept the alternative - [ ] reject the null ### Conclusion As such, the final conclusion is that there is [ ] sufficient evidence to conclude the standard deviation in cereal box weight is [ ] than [ ]. ### Graphs / Diagrams Explanation If there are any graphs or diagrams, explain them in detail (none provided in the given image). For further information or questions about this topic, please refer to our detailed resources on hypothesis testing and standard deviation analysis.
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