The U.S. Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car.Suppose that for a random sample of 75 Buffalo residents the mean is 25 miles a day. The standard deviation of the population (Buffaloresidents) is 5.1 miles a day. For an independent random sample of 60 Boston residents the mean is 23 miles a day. The standard deviation ofthe population (Boston residents) is 8.2 miles a day.Consider the following hypothesis test. Mean 1 = Buffalo residents ; Mean 2 = Boston ResidentsHo : 1 – H2 = 0H : H1 - 42 0At alpha = 0.05 what is your conclusion?0.05-3.6 0002 0002 0001 0001 .0001 .0001 000 0001 .0001 00010.010.020.040.060.070.090.000.030.08-3.5.00020002.00020002.0002.00020002.0002.00020002-3.4 0003.0003.0003 0003 .0003 00030003 0003 0003 0002-33 000500050005 0004 .0004 .00040004 00040004 0003-32 0007-3.1 0010.00070006 0006 .0006 .00060006 0005.0005 00050009.0009 0009 .0008 .00080008 0008 0007 0007-3.0 0013-29 0019„00130013 0012 .0012 .00110011.00110010 0010.001800180017.0016.00160015001500140014-280026002500240023.0023002200210021.00200019

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Description: The U.S. Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car.Suppose that for a random sample of 75 Buffalo residents the mean is 25 miles a day. The standard deviatio

There are two independent populations. Those which are named as Buffalo residents and Boston…

Math

Statistics

The U.S. Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car. Suppose that for a random sample of 75 Buffalo residents the mean is 25 miles a day. The standard deviation of the population (Buffalo residents) is 5.1 miles a day. For an independent random sample of 60 Boston residents the mean is 23 miles a day. The standard deviation of the population (Boston residents) is 8.2 miles a day. Consider the following hypothesis test. Mean 1 = Buffalo residents ; Mean 2 = Boston Residents Ho : H1 - H2 = 0 H : 1 – 42 +0 At alpha = 0.05 what is your conclusion?

The U.S. Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car. Suppose that for a random sample of 75 Buffalo residents the mean is 25 miles a day. The standard deviation of the population (Buffalo residents) is 5.1 miles a day. For an independent random sample of 60 Boston residents the mean is 23 miles a day. The standard deviation of the population (Boston residents) is 8.2 miles a day. Consider the following hypothesis test. Mean 1 = Buffalo residents ; Mean 2 = Boston Residents Ho : H1 - H2 = 0 H : 1 – 42 +0 At alpha = 0.05 what is your conclusion?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

Topic Video

Question

The U.S. Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car.
Suppose that for a random sample of 75 Buffalo residents the mean is 25 miles a day. The standard deviation of the population (Buffalo
residents) is 5.1 miles a day. For an independent random sample of 60 Boston residents the mean is 23 miles a day. The standard deviation of
the population (Boston residents) is 8.2 miles a day.
Consider the following hypothesis test. Mean 1 = Buffalo residents ; Mean 2 = Boston Residents
Ho : 1 – H2 = 0
H : H1 - 42 0
At alpha = 0.05 what is your conclusion?
0.05
-3.6 0002 0002 0001 0001 .0001 .0001 000 0001 .0001 0001
0.01
0.02
0.04
0.06
0.07
0.09
0.00
0.03
0.08
-3.5
.0002
0002
.0002
0002
.0002
.0002
0002
.0002
.0002
0002
-3.4 0003
.0003
.0003 0003 .0003 0003
0003 0003 0003 0002
-33 0005
0005
0005 0004 .0004 .0004
0004 0004
0004 0003
-32 0007
-3.1 0010
.0007
0006 0006 .0006 .0006
0006 0005
.0005 0005
0009
.0009 0009 .0008 .0008
0008 0008 0007 0007
-3.0 0013
-29 0019
„0013
0013 0012 .0012 .0011
0011
.0011
0010 0010
.0018
0018
0017
.0016
.0016
0015
0015
0014
0014
-28
0026
0025
0024
0023
.0023
0022
0021
0021
.0020
0019

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