A pin manufacturing company made a scientific study to find out the number of defective items in a pack of 250 bolts of the same kind. For a "size A" bolt, the chance of manufacturing a defective item is 2%. For a "size B", 4%. The company, to persuade buyers to buy, guarantees that in a pack, no more than 10 pins are defective. If 11 or more are defective, the customers have all the right to request for a refund. Suppose that a customer bought one pack of "size B" pins, what are the chances of the company keeping up its claim?
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- An insurance company found that 2.4% of male drivers between the ages of 18 and 25 are involved in serious accidents annually. To simplify the analysis, assume that every such accident costs the insurance company $62,000 and that a driver can only have one of these accidents in a year. Complete parts (a) through (c). (a) If the company charges $2,600 for such coverage, what is the chance that it loses money on a single policy? P(loses money)= .024 (Type an integer or a decimal.) (b) Suppose that the company writes 1,000 such policies to a collection of drivers. What is the probability that the company makes a profit on these policies? Assume that the drivers don't run into each other and behave independently. P(profit) = .976 (Round to five decimal places as needed.)Do people get stressed out when other people watch them work? To find out, Sean and Shelby recruited 30 volunteers to take part in an experiment. Fifteen of the subjects were randomly assigned to complete a word search puzzle while Sean and Shelby stood close by and visibly took notes. The remaining 15 were assigned to complete a word search puzzle while Sean and Shelby stood at a distance. After each subject completed the word search, they completed a second word search under the opposite treatment. The amount of time required to complete each puzzle was recorded for each subject. Explain why these are paired data. These are paired data because they result from Seanand Shelby recorded with Sean and Shelby standing close by and, during a separate time, while Sean and ShelbyA mathematics researcher has pointed out a problem with massive, untargeted wiretaps. To illustrate the problem, he supposes that one out of every million citizens of a certain country has terrorist ties. Furthermore, he supposes that the terrorist profile is 98.4% accurate, so that if a person has terrorist ties, the profile will pick them up 98.4% the time, and if the person does not have terrorist ties, the profile will accidentally pick them up only 1.6% of the time. Given that the profile has picked up a person, what is t probability that the person actually has terrorist ties? The probability is (Type an integer or a decimal rounded to six decimal places as needed.)
- Suppose I flip a fair coin n = 20 times. A psychic tries to predict the outcome before each flip. Three researchers have different ideas about the psychic's ability. There is Sydney, the Skeptic (S), who thinks the psychic's success rate is between 49% and 51%. There is Morgan, the Mark, M, who thinks that the psychic's success rate is 80%. And there is Carter, the Cynic (C), who thinks the psychic's success rate is 10%. Specifically: S+ 0 ~ U(.49, .51) M + 0 = .80 C0 = .10 %3D In all cases, assume the number of successful predictions follows a binomial distribution with success rate 0. Usek for the number of successes and n for the number of trials. Given all that: Determine the formula for the Bayes factor (a.k.a., likelihood ratio) supporting Carter over Morgan. Call that Bayes factor Bc:M Determine the formula for the Bayes factor (a.k.a., likelihood ratio) supporting Morgan over Sydney. Call that Bayes factor BM:S Determine the formula for the Bayes factor (a.k.a., likelihood…A teacher announces a pop quiz for which the student is completely unprepared. The quiz consists of 20 true-false questions. The student has no choice but to guess the answer randomly for all 20 questions. The accompanying table gives the 20 correct answers, which were actually randomly generated. Complete parts a. and b. below. a. How many questions can the student expect to answer correctly simply by guessing? b. What percentage of answers were true, and what percentage would you expect? Why are they not necessarily identical? The percentage of answers that were true was? The expected percentage of answers that would be true is? Why are these answers not necessarily identical? A. With random phenomena, the proportion of times that something happens is highly predictable in the short run. B. With random phenomena, the proportion of times that something happens is highly random and variable in the short run. C. With random phenomena, the…A large retail lawn care dealer currently provides a 2-year warranty on all lawn mowers sold at its stores. A new employee suggested that the dealer could save money by just not offering the warranty. To evaluate this suggestion, the dealer randomly decides whether or not to offer the warranty to the next 50 customers who enter the store and express an interest in purchasing a lawnmower. Out of the 25 customers offered the warranty, 10 purchased a mower as compared to 4 of 25 not offered the warranty. a. Place a 95% confidence interval on 7₁ - 72, the difference in the proportions of customers purchasing lawnmowers with and without the warranty. b. Test the research hypothesis that offering the warranty will increase the propor- tion of customers who will purchase a mower. Use a = .05. c. Are the conditions for using a large-sample test to answer the question in part (b) satisfied? If not, apply an exact procedure,
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- A new game is being introduced at the Hard Rock Cafe. A ball is spun around a wheel until it comes to rest in one of many spots. Whatever is listed in that spot will be the player's winnings. If the wheel has 7 spots labeled $1, 9 spots labeled $2, and 6 spots labeled $10, how much should a player expect to win on average? Round to the nearest cent.B. Perimeter Shot - A perimeter shot, also known as a mid-range shot, is a jump shot or general field goal attempt that an offensive player can take inside of the three-point line and is worth 2 points. To practice this, Piel has to choose four different shooting spots among the five different spots in where he is comfortable of shooting. In previous games, his shot selection is 5% from the right baseline (Spot 1), 15% from the right elbow (Spot 2), 20% from the top of the key (Spot 3), 25% from the left elbow (Spot 4) and 35% from the left baseline (Spot 5). In this drill, a shooting spot can be selected once, multiple times, or not at all. This drill illustrates a random experiment with distribution. To help Piel decide, below is the partial table for the means and standard deviations of the random variable, Y, or the number of times he shoot the ball in a shooting spot. Shooting Spot E[Y] SD[Y] Spot 1 0.2 0.4359 Spot 2 0.6 0.7141 Spot 3 0.8 0.8000 Spot 4 the mean of 1.4 by will…