A pharmaceutical company would like to investigate the response time of a COVID-19 rapid test. The company claims that the response time is 16 minutes. To investigate this claim, the company decided to consider the response time of a random sample of 20 tests. Rapid Test Kit COVID-19 Results in 15 minutes Given: The response times has a normal distribution with a standard deviation of o = 2. The company wishes to test this claim at a = 0.1 level of significance. The value of the test statistic is z = -0.74.
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- In a study of pulse rates of men, a simple random sample of 150 men results in a standard deviation of 11.4 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.05 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute; see the accompanying StatCrunch display for this test. What do the results indicate about the effectiveness of using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o in this case? Assume that the simple random sample is selected from a normally distributed population. Click the icon to view the StatCrunch display. Let o denote population standard deviation of the pulse rates of men (in beats per minute). Identify the null and alternative hypotheses. Ho: o H₁:…A scale measuring confidence in the media was administered to a random sample of politically-affiliated Americans, with higher scores indicating greater levels of confidence. A sample of 26 Democrats had a mean score of 8.2 on the scale with a standard deviation of 1.5. A sample of 24 Republicans scored an average of 7.8 with a standard deviation of 1.1. Is there a significant difference between Democrats and Republicans regarding confidence in the media? Conduct a significance test with alpha = .05. STEP ONE: What is the fourth requirement for this significance test? 1. Independent random samples 2. Interval-ratio variable of confidence in the media (technically ordinal) 3. Normal sampling distribution assumed 4.The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.6 years. He then randomly selects records on 31 laptops sold in the past and finds that the mean replacement time is 3.1 years.Assuming that the laptop replacement times have a mean of 3.3 years and a standard deviation of 0.6 years, find the probability that 31 randomly selected laptops will have a mean replacement time of 3.1 years or less.P(M < 3.1 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality? No. The probability of obtaining this data is high enough…
- The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.2 years and a standard deviation of 0.5 years. He then randomly selects records on 35 laptops sold in the past and finds that the mean replacement time is 3 years.Assuming that the laptop replacment times have a mean of 3.2 years and a standard deviation of 0.5 years, find the probability that 35 randomly selected laptops will have a mean replacment time of 3 years or less.P(x-bar < 3 years) = Enter your answer as a number accurate to 4 decimal places. The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.963 g and a standard deviation of 0.315 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a…An avionics company uses a new production method to manufacture aircraft altimeters. A single random sample of new altimeters resulted in the errors listed below. Use a 5% significance level to test the claim that the new production method has errors with a standard deviation greater than 32.2 ft, which was the standard deviation for the old production model (o). If it appears that the standard deviation is greater, does the new production method appear to be better or worse than the old method? Should the company take any action? -42 78 -22 -72 -45 15 17 51 -5 -53 -9 -109 Find the upper and lower boundaries of the 95% confidence interval for o. 98 37 32 73 89The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.6 years and a standard deviation of 0.4 years. He then randomly selects records on 48 laptops sold in the past and finds that the mean replacement time is 3.4 years. Assuming that the laptop replacement times have a mean of 3.6 years and a standard deviation of 0.4 years, find the probability that 48 randomly selected laptops will have a mean replacement time of 3.4 years or less. P(M < 3.4 years)=__________
- Bowker and Lieberman (1972) gave the results for tests of two thermostats used in irons that were made by an old supplier and a new supplier. 18 thermostats were sampled from the old supplier and 21 thermostats were sampled from the new supplier. The actual temperatures measured with a thermocouple and were recorded. The sample from the old supplier had a mean of x₁ =549.8 and a standard deviation of s₁=9.6. The sample from the new supplier had a mean of x₂=550.4 and a standard deviation of s2=11.2. Determine the value of the pooled standard deviation Sp Sp = ... (Record to two decimal places.) 4The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.4 years. He then randomly selects records on 25 laptops sold in the past and finds that the mean replacement time is 3.2 years.Assuming that the laptop replacement times have a mean of 3.3 years and a standard deviation of 0.4 years, find the probability that 25 randomly selected laptops will have a mean replacement time of 3.2 years or less.P(M < 3.2 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality? No. The probability of obtaining this data is high enough…The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.1 years and a standard deviation of 0.6 years. He then randomly selects records on 41 laptops sold in the past and finds that the mean replacement time is 3.9 years.Assuming that the laptop replacement times have a mean of 4.1 years and a standard deviation of 0.6 years, find the probability that 41 randomly selected laptops will have a mean replacement time of 3.9 years or less.P(M < 3.9 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality?
- The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.7 years and a standard deviation of 0.5 years. He then randomly selects records on 52 laptops sold in the past and finds that the mean replacement time is 3.6 years. Assuming that the laptop replacement times have a mean of 3.7 years and a standard deviation of 0.5 years, find the probability that 52 randomly selected laptops will have a mean replacement time of 3.6 years or less. P(M3.6 years) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, does it appear that the computer store has been given laptops of lower than average quality? Yes. The probability of this data is unlikely to have occurred…The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.8 years and a standard deviation of 0.5 years. He then randomly selects records on 36 laptops sold in the past and finds that the mean replacement time is 3.5 years.Assuming that the laptop replacment times have a mean of 3.8 years and a standard deviation of 0.5 years, find the probability that 36 randomly selected laptops will have a mean replacment time of 3.5 years or less.P(¯xx¯ < 3.5 years) = Enter your answer as a number accurate to 4 decimal places.Based on the result above, does it appear that the computer store has been given laptops of lower than average quality?5.37 Dental anxiety study. To gauge their fear of going to a den- tist, a random sample of adults completed the Modified Dental Anxiety Scale questionnaire (BMC Oral Health, Vol. 9, 2009). Scores on the scale range from zero (no anx- iety) to 25 (extreme anxiety). The mean score was 11 and the standard deviation was 4. Assume that the distribution of all scores on the Modified Dental Anxiety Scale is ap- proximately normal with µ = 11 and o = 4. a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for your score. b. Find the probability that someone scores between 10 and 15 on the Modified Dental Anxiety Scale. c. Find the probability that someone scores above 20 on the Modified Dental Anxiety Scale.