a petroleum crude oil with a specific gravity of 0.865 is flowing through a piping arrangement as depicted below. The mass flow rate is 1.45 kg/s entering pipe 1. The flow divides equally in pipes 3.The steel pipes used are schedule 40. Calculate the following: (a) The mass flow rates in pipes 1 and 3. (b) The average velocity in pipes 1,2 and 3. (c) The mass velocity in pipe 2. Given value for pic. 2- in schedule 40 Inside diameter = 2.067in Crosss sectional area = = 0.02330ft^2 3- in schedule 40 Inside diameter = 3.068in Cross sectional area = 1 1/2 in schedule 40 Inside diameter = 1.610in Cross sectional area = = 0.0513ft^2 = 0.01414ft^2 Please show your complete solution and show units when solving thanks.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
a petroleum crude oil with a specific gravity of
0.865 is
flowing through a piping arrangement as depicted
below.
The mass flow rate is 1.45 kg/s entering pipe 1. The
flow
divides equally in pipes 3.The steel pipes used are
schedule 40. Calculate the following:
(a) The mass flow rates in pipes 1 and 3.
(b) The average velocity in pipes 1,2 and 3.
(c) The mass velocity in pipe 2.
Given value for pic.
2- in schedule 40
Inside diameter = 2.067in
Crosss sectional area = 0.02330ft^2
3- in schedule 40
Inside diameter = 3.068in
Cross sectional area = 0.0513ft^2
1 1/2 in schedule 40
Inside diameter = 1.610in
Cross sectional area = 0.01414ft^2
Please show your complete solution and show
units when solving thanks.
Transcribed Image Text:a petroleum crude oil with a specific gravity of 0.865 is flowing through a piping arrangement as depicted below. The mass flow rate is 1.45 kg/s entering pipe 1. The flow divides equally in pipes 3.The steel pipes used are schedule 40. Calculate the following: (a) The mass flow rates in pipes 1 and 3. (b) The average velocity in pipes 1,2 and 3. (c) The mass velocity in pipe 2. Given value for pic. 2- in schedule 40 Inside diameter = 2.067in Crosss sectional area = 0.02330ft^2 3- in schedule 40 Inside diameter = 3.068in Cross sectional area = 0.0513ft^2 1 1/2 in schedule 40 Inside diameter = 1.610in Cross sectional area = 0.01414ft^2 Please show your complete solution and show units when solving thanks.
2-in. pipe
2
3-in. pipe
11/2-in. pipe
11/2-in. pipe
Transcribed Image Text:2-in. pipe 2 3-in. pipe 11/2-in. pipe 11/2-in. pipe
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