1.35 kg is suspended by a A sphere with diameter D = 0.12 m and mass m = jet of air as shown below. The drag coefficient for this sphere can be taken as 0.45 (dimensionless). The air has a constant density pair = 1.20 kg/m³. Any buoyancy effects will be negligibly small. You may neglect any gravity and frictional effects for the flow between the pressure gage and the exit. The upper area is A1= 0.03 m². The lower area is A2 = 0.09 m². Area = Aj = (0.03 m² 1 Air Area = A2 = 0.09 m² Pressure gage (1.a) What is the reading on the pressure gauge [ kPa ]?

Introduction to Chemical Engineering Thermodynamics
8th Edition
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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A sphere with diameter \( D = 0.12 \, \text{m} \) and mass \( m = 1.35 \, \text{kg} \) is suspended by a jet of air as illustrated below. The drag coefficient for this sphere can be taken as \( 0.45 \) (dimensionless). The air has a constant density \( \rho_{\text{air}} = 1.20 \, \text{kg/m}^3 \). Any buoyancy effects will be negligibly small.

You may neglect any gravity and frictional effects for the flow between the pressure gauge and the exit.

- The upper area is \( A_1 = 0.03 \, \text{m}^2 \).
- The lower area is \( A_2 = 0.09 \, \text{m}^2 \).

**Diagram Explanation:**

In the diagram, a sphere is suspended in the air by an upward air jet. The setup includes a vertical air jet tube with a pressure gauge mounted on the side.

- **Sphere:** Shown at the top of the diagram, aligning with the airflow.
- **Air Jet Tube:** The air flows upward through the tube having two distinct cross-sectional areas:
  - **Upper area \( A_1 = 0.03 \, \text{m}^2 \):** The section closest to the sphere.
  - **Lower area \( A_2 = 0.09 \, \text{m}^2 \):** The section where the pressure gauge is attached.
- **Air Direction:** The diagram uses arrows to indicate the upward direction of air flow.

**Question:**

(1.a) What is the reading on the pressure gauge \([ \text{kPa} ]\)?
Transcribed Image Text:A sphere with diameter \( D = 0.12 \, \text{m} \) and mass \( m = 1.35 \, \text{kg} \) is suspended by a jet of air as illustrated below. The drag coefficient for this sphere can be taken as \( 0.45 \) (dimensionless). The air has a constant density \( \rho_{\text{air}} = 1.20 \, \text{kg/m}^3 \). Any buoyancy effects will be negligibly small. You may neglect any gravity and frictional effects for the flow between the pressure gauge and the exit. - The upper area is \( A_1 = 0.03 \, \text{m}^2 \). - The lower area is \( A_2 = 0.09 \, \text{m}^2 \). **Diagram Explanation:** In the diagram, a sphere is suspended in the air by an upward air jet. The setup includes a vertical air jet tube with a pressure gauge mounted on the side. - **Sphere:** Shown at the top of the diagram, aligning with the airflow. - **Air Jet Tube:** The air flows upward through the tube having two distinct cross-sectional areas: - **Upper area \( A_1 = 0.03 \, \text{m}^2 \):** The section closest to the sphere. - **Lower area \( A_2 = 0.09 \, \text{m}^2 \):** The section where the pressure gauge is attached. - **Air Direction:** The diagram uses arrows to indicate the upward direction of air flow. **Question:** (1.a) What is the reading on the pressure gauge \([ \text{kPa} ]\)?
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