A person stands on a scale inside an elevator at rest (see the figure below). The scale reads W = 625 N.aW(a) What is the person's mass?kg(b) The elevator accelerates upward momentarily at the rate of a = 4 m/s?. What does the scale read then?N(c) The elevator then moves with a steady speed of 6 m/s. What does the scale read now?

Name: A person stands on a scale inside an elevator at rest (see the figure
Uploaded: 2022-11-23T13:49:28.000Z
Channel: Bartleby
Description: A person stands on a scale inside an elevator at rest (see the figure below). The scale reads W = 625 N.aW(a) What is the person's mass?kg(b) The elevator accelerates upward momentarily at the rate of a = 4 m/s?. What does the scale read then?N(c) T

weight of the person W = 625 N acceleration due to gravity g =9.8 ms2 a) Mass of the person m = Wg…

Answered: A person stands on a scale inside an…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

Practice Pack

A person stands on a scale inside an elevator at rest (see the figure below). The scale reads W = 625 N.
a
W
(a) What is the person's mass?
kg
(b) The elevator accelerates upward momentarily at the rate of a = 4 m/s?. What does the scale read then?
N
(c) The elevator then moves with a steady speed of 6 m/s. What does the scale read now?

Expert Solution

Step 1

weight of the person $W = 625 N$

acceleration due to gravity $g = 9.8 \frac{m}{s^{2}}$

Mass of the person

$m = \frac{W}{g} = \frac{625}{9.8} = 63.77 k g$

Better your learning with

Practice Pack

Better your learning with

Practice Pack

Trending now

This is a popular solution!

Learn your way

Includes step-by-step video

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions