A pendulum clock has a rod with a period of 2 s at 20 If the temperature rises to 30 °C, how much does the clock lose or gain in one week? Treat the rod as a physical pendu- lum pivoted at one end. (See Example 15.8.)
Properties of sound
A sound wave is a mechanical wave (or mechanical vibration) that transit through media such as gas (air), liquid (water), and solid (wood).
Quality Of Sound
A sound or a sound wave is defined as the energy produced due to the vibrations of particles in a medium. When any medium produces a disturbance or vibrations, it causes a movement in the air particles which produces sound waves. Molecules in the air vibrate about a certain average position and create compressions and rarefactions. This is called pitch which is defined as the frequency of sound. The frequency is defined as the number of oscillations in pressure per second.
Categories of Sound Wave
People perceive sound in different ways, like a medico student takes sound as vibration produced by objects reaching the human eardrum. A physicist perceives sound as vibration produced by an object, which produces disturbances in nearby air molecules that travel further. Both of them describe it as vibration generated by an object, the difference is one talks about how it is received and other deals with how it travels and propagates across various mediums.
![(5.)(1) A pendulum clock has a rod with a period of 2 s at 20 °C.
If the temperature rises to 30 °C, how much does the clock
lose or gain in one week? Treat the rod as a physical pendu-
lum pivoted at one end. (See Example 15.8.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e948f6-fd6f-485f-942e-c931230f8579%2F657ae161-1682-4682-9aa0-0cbe4658d422%2Fd0qktt_processed.png&w=3840&q=75)
![V = L
do
dt
77
= (0.25 m)(0.17) (2m) cos( +
= -0.123 m/s
EXAMPLE 15.8: A uniform rod of mass m and length L is
freely pivoted at one end. (a) What is the period of its oscilla-
tion? (b) What is the length of a simple pendulum with the same
period?
Solution: (a) The moment of inertia of a rod about one end is
I= mL² (Eq. 11.18). The center of mass of a uniform rod is at
its center, so d = L/2 in Eq. 15.17. The period is
2L
3g
T = 2
(b) Comparing Eq. 15.17 with T= 27 VL/g for a simple pendu-
lum, we see that the period of a physical pendulum is the same
as that of an "equivalent" simple pendulum of length
For the uniform rod
Leg
mL²/3
mgL/2
Leq
=
-
I
md
mL²/3
(mL/2)
2п
2L
3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e948f6-fd6f-485f-942e-c931230f8579%2F657ae161-1682-4682-9aa0-0cbe4658d422%2Fzij3mrd_processed.jpeg&w=3840&q=75)
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