Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The following ingredients are thrown into an insulated cup. Find the equilibrium temperature of the mixture. There are no phase changes. (kg` Volume (m³) Density \m³ Specific Heat () Initial Temperature (K) Name \kg K, Water 1 1000 4181 273 Gold 0.1 19,300 10,490 4500 130 200 Silver 0.05 235 550 Titanium 0.5 527 783 Nickle 0.15 8890 443 600 Brass 0.1 8500 385 780

The following ingredients are thrown into an insulated cup. Find the equilibrium temperature of the mixture. There are no phase changes. (kg` Volume (m³) Density \m³ Specific Heat () Initial Temperature (K) Name \kg K, Water 1 1000 4181 273 Gold 0.1 19,300 10,490 4500 130 200 Silver 0.05 235 550 Titanium 0.5 527 783 Nickle 0.15 8890 443 600 Brass 0.1 8500 385 780

icon
Related questions
Question
**Problem Description:** The following ingredients are placed into an insulated cup. Determine the equilibrium temperature of the mixture. Note that there are no phase changes. **Table of Ingredients:** | Name | Volume (m³) | Density (kg/m³) | Specific Heat (J/kg·K) | Initial Temperature (K) | |-----------|-------------|-----------------|------------------------|-------------------------| | Water | 1 | 1000 | 4181 | 273 | | Gold | 0.1 | 19,300 | 130 | 200 | | Silver | 0.05 | 10,490 | 235 | 550 | | Titanium | 0.5 | 4500 | 527 | 783 | | Nickle | 0.15 | 8890 | 443 | 600 | | Brass | 0.1 | 8500 | 385 | 780 | **Explanation:** - **Water**: Has a relatively high specific heat, which indicates it requires a substantial amount of energy to change its temperature. - **Gold**: Notable for its high density but low specific heat, meaning it heats up and cools down quickly. - **Silver**: Moderate density and low specific heat with a higher initial temperature compared to water and gold. - **Titanium**: Has a low specific heat relative to its high initial temperature, contributing substantially to the heat exchange. - **Nickle**: Similar to titanium in specific heat but with slightly lower initial temperature. - **Brass**: Functions similarly to silver, with moderate density and low specific heat. These components, each with different thermal properties and initial temperatures, are combined, and their interaction within an insulated environment allows for calculation of a central equilibrium temperature. Understanding these concepts is crucial when analyzing heat transfer and material properties in thermodynamics.
Transcribed Image Text:**Problem Description:** The following ingredients are placed into an insulated cup. Determine the equilibrium temperature of the mixture. Note that there are no phase changes. **Table of Ingredients:** | Name | Volume (m³) | Density (kg/m³) | Specific Heat (J/kg·K) | Initial Temperature (K) | |-----------|-------------|-----------------|------------------------|-------------------------| | Water | 1 | 1000 | 4181 | 273 | | Gold | 0.1 | 19,300 | 130 | 200 | | Silver | 0.05 | 10,490 | 235 | 550 | | Titanium | 0.5 | 4500 | 527 | 783 | | Nickle | 0.15 | 8890 | 443 | 600 | | Brass | 0.1 | 8500 | 385 | 780 | **Explanation:** - **Water**: Has a relatively high specific heat, which indicates it requires a substantial amount of energy to change its temperature. - **Gold**: Notable for its high density but low specific heat, meaning it heats up and cools down quickly. - **Silver**: Moderate density and low specific heat with a higher initial temperature compared to water and gold. - **Titanium**: Has a low specific heat relative to its high initial temperature, contributing substantially to the heat exchange. - **Nickle**: Similar to titanium in specific heat but with slightly lower initial temperature. - **Brass**: Functions similarly to silver, with moderate density and low specific heat. These components, each with different thermal properties and initial temperatures, are combined, and their interaction within an insulated environment allows for calculation of a central equilibrium temperature. Understanding these concepts is crucial when analyzing heat transfer and material properties in thermodynamics.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer