A past survey of 1,068,000 students taking a standardized test revealed that 7.6% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 95% confidence interval for the difference between proportions p1−p2 by using the following inequality. Assume the samples are random and independent. The confidence interval is ___
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A past survey of 1,068,000 students taking a standardized test revealed that 7.6% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 95% confidence interval for the difference between proportions p1−p2 by using the following inequality. Assume the samples are random and independent.
The confidence interval is ___ <p1 − p2<_____
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- A past survey of 1,068,000 students taking a standardized test revealed that 9.6% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 95% confidence interval for the difference between proportions p, -P2 by using the following inequality. Assume the samples are random and independent. P,9 P292A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 223 people in the sample are newspaper readers. Calculate a 90%-confidence interval for the percentage of people (age 18 and over) in that town who read newspapers. Choose the closest answer. a. (19.7%, 24.9%) b. (21.5%, 23.0%) c. (21.0%, 23.5%) d. (20.1%, 24.5%)A genetic experiment with peas resulted in one sample of offspring that consisted of 441 green peas and 164 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?From a random sample of 120 students, 95 rated a case of plagiarism as unethical. Using this information, you computed a confidence interval extending from 0.68 to 0.76 for the population proportion. What is the confidence coefficient of the interval?2) A random sample of 120 students at a high school was asked whether they would ask their father or mother for help with a homework assignment in science. A second random sample of 150 different students was asked the same question for an assignment in history. Fifty-four students in the first sample and 72 students in the second sample replied that they turned to their mother rather than their father for help. Construct a 99% confidence interval for the difference of the two proportions and express it as . (Round both numbers to the 4th decimal placIn a random sample of 800 men aged 25 to 35 years, 24% said they live with one or both parents. In another sample of 850 women of the same age group, 18% said that they live with one or both parents.A. Construct a 95% confidence interval for the difference between the proportions of all men and all women aged 25 to 35 years who live with one or both parents.B. Test at the 2% significance level whether the two population proportions are different.C. Repeat the test of part b using the p-value approach.A genetic experiment with peas resulted in one sample of offspring that consisted of 443 green peas and 167 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?A past survey of 1,068,000 students taking a standardized test revealed that 9.6% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, - P2 by using the following inequality. Assume the samples are random and independent. P191 + Zc P191 P292 P292A genetic experiment with peas resulted in one sample of offspring that consisted of 442 green peas and 160 yellow peas. A. Construct a 95% confidence interval to estimate of the percentage of yellow peas. B. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? A. Construct a 95% confidence interval. Express the percentages in decimal form. ___ <p<___ (Round to three decimal places as needed.)A researcher surveyed college students in the United States on the typical amount of time each day that they spend interacting with different types of media (television, social media, Internet-connected devices, game consoles, etc.) The researcher found that the mean amount of time that college students spent watching television each day is 135 minutes with a 95% confidence interval of (105, 165). a. State the conclusion the researcher can make from this confidence interval. b. What is the margin of error for the confidence interval?A past survey of 1,068,000 students taking a standardized test revealed that 9.8% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p, by using the following inequality. Assume the samples are random and independent. A A P191 P292 + Zc n1 P11 P292In a survey of 3242 adults aged 57 through 85 years, it was found that 82.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3242 subjects used at least one prescription medication? ____ (Round to the nearest integer as needed.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. ____%<p<____% (Round to one decimal place as needed.) c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). B. 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