A past survey of 1,068,000 students taking a standardized test revealed that 8.5% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p2 by using the following inequality. ASsume the samples are random and independent. P191 P292 (ô, - P)-

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A past survey of 1,068,000 students taking a standardized test revealed that 8.5% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the
students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p2 by using the following inequality. ASsume the samples are random and independent.
P191 P292
(ô, - P)-
<P, -P2 < (P, -P2) +
P191 P292
+Z.
n1
n1
n2
n2
The confidence interval is
|<P1 - P2<
(Round to three decimal places as needed.)
Transcribed Image Text:A past survey of 1,068,000 students taking a standardized test revealed that 8.5% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p2 by using the following inequality. ASsume the samples are random and independent. P191 P292 (ô, - P)- <P, -P2 < (P, -P2) + P191 P292 +Z. n1 n1 n2 n2 The confidence interval is |<P1 - P2< (Round to three decimal places as needed.)
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