**Physics Problem: Calculating Force on a Charged Particle in a Magnetic Field**A particle with a charge of \( -1.24 \times 10^{-8} \, \text{C} \) is moving with an instantaneous velocity given by:\[\vec{v} = (4.19 \times 10^4 \, \text{m/s}) \hat{\imath} + (-3.85 \times 10^4 \, \text{m/s}) \hat{\jmath}\]### Part A**Problem Statement:**What is the force exerted on this particle by a magnetic field \( \vec{B} = (2.80 \, \text{T}) \hat{\imath} \)?**Instructions:**Express the \( x, y, \) and \( z \) components of the force in newtons, separated by commas.\[ F_x, F_y, F_z = [ \quad \quad \] Submit your answer using the "Submit" button.### Part B**Problem Statement:**What is the force exerted on this particle by a magnetic field \( \vec{B} = (2.80 \, \text{T}) \hat{k} \)?**Instructions:**Express the \( x, y, \) and \( z \) components of the force in newtons, separated by commas.\[ F_x, F_y, F_z = [ \quad \quad \]Submit your answer using the "Submit" button.---**Additional Features:**- Options to utilize vector and Greek letter input via specialized input tools.- "Request Answer" option available for assistance.- "Provide Feedback" link for submitting feedback related to this problem.This exercise helps students practice calculating the force on a charged particle moving in a magnetic field by applying the Lorentz force law.

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Answered: A particle with a charge of -1.24x10-8…

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A particle with a charge of -1.24x10-8 C is moving with instantaneous velocity = (4.19x 104 m/s)i + (-3.85x104 m/s)j. What is the force exerted on this particle by a magnetic field B = (2.80 T)i?