A particle of charge 2.0 x 10-8 C experiences an upward force of magnitude 1.5 x 10-6 N when it is placed at a particular point in space. Hint a. What is the electric field at that point? The electric field at that point is b. If a charge q = -3.0 x 10-8 C is placed there, what is the force on it? The force is in Select an answer direction with magnitude (Use "E notation" to give your answer in scientific notation, e.g. "3.14E-12" for 3.14 x 10-¹2.) N/C.

icon
Related questions
Question
100%
**Electromagnetic Field Concepts**

**Problem Statement:**
A particle of charge \(2.0 \times 10^{-8}\) C experiences an upward force of magnitude \(1.5 \times 10^{-6}\) N when it is placed at a particular point in space.

**Questions:**

a. **What is the electric field at that point?**

   - To find the electric field (\(E\)) at that point, use the relation:
     \[
     E = \frac{F}{q}
     \]
   - Where \(F\) is the force (\(1.5 \times 10^{-6}\) N) and \(q\) is the charge (\(2.0 \times 10^{-8}\) C).
   - The electric field at that point is \(\_\_\_\_\_\_\_\_\_\_ \, \text{N/C}\).

b. **If a charge \(q = -3.0 \times 10^{-8}\) C is placed there, what is the force on it?**

   - The force (\(F\)) on the charge can be calculated using:
     \[
     F = qE
     \]
   - Determine the magnitude and direction of the force.
   - The force is in \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\) direction with magnitude \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \text{N}\).

**Instructions:**
- Use "E notation" to express your answers in scientific notation, e.g., "3.14E-12" for \(3.14 \times 10^{-12}\).

**Features:**
- **Question Help:** If you need assistance, you can message the instructor.
- **Submit Question:** Once you've completed the calculations, submit your answer.

---

This problem involves basic electrostatics principles, focusing on the understanding of electric fields and forces on charges. The solution involves direct calculation using the given formulas.
Transcribed Image Text:**Electromagnetic Field Concepts** **Problem Statement:** A particle of charge \(2.0 \times 10^{-8}\) C experiences an upward force of magnitude \(1.5 \times 10^{-6}\) N when it is placed at a particular point in space. **Questions:** a. **What is the electric field at that point?** - To find the electric field (\(E\)) at that point, use the relation: \[ E = \frac{F}{q} \] - Where \(F\) is the force (\(1.5 \times 10^{-6}\) N) and \(q\) is the charge (\(2.0 \times 10^{-8}\) C). - The electric field at that point is \(\_\_\_\_\_\_\_\_\_\_ \, \text{N/C}\). b. **If a charge \(q = -3.0 \times 10^{-8}\) C is placed there, what is the force on it?** - The force (\(F\)) on the charge can be calculated using: \[ F = qE \] - Determine the magnitude and direction of the force. - The force is in \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\) direction with magnitude \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \, \text{N}\). **Instructions:** - Use "E notation" to express your answers in scientific notation, e.g., "3.14E-12" for \(3.14 \times 10^{-12}\). **Features:** - **Question Help:** If you need assistance, you can message the instructor. - **Submit Question:** Once you've completed the calculations, submit your answer. --- This problem involves basic electrostatics principles, focusing on the understanding of electric fields and forces on charges. The solution involves direct calculation using the given formulas.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS