A particle moves in the x-y plane with a y-component of velocity in feet per second given by v, = 5.5t with t in seconds. The acceleration of the particle in the x-direction in feet per second squared is given by a, = 5.6t with t in seconds. When t = 0, y = 2.7 ft, x = 0, and v, = 0. The equation of the path of the particle can be written in the form (y - b)? = cx?. Find the constants b and c and calculate the magnitude of the velocity v of the particle for the instant when its x-coordinate reaches 20.4 ft. Answer: b = ft C = ft When x = 20.4 ft, v = ft/sec

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Chapter1: Units, Trigonometry. And Vectors
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A particle moves in the x-y plane with a y-component of velocity in feet per second given by v, = 5.5t with t in seconds. The acceleration of the particle in the x-direction in feet per
second squared is given by a, = 5.6t with t in seconds. When t = 0, y = 2.7 ft, x = 0, and v, = 0. The equation of the path of the particle can be written in the form (y - b)? = cx?. Find
the constants b and c and calculate the magnitude of the velocity v of the particle for the instant when its x-coordinate reaches 20.4 ft.
Answer:
b =
ft
C =
ft
When x = 20.4 ft, v =
ft/sec
Transcribed Image Text:A particle moves in the x-y plane with a y-component of velocity in feet per second given by v, = 5.5t with t in seconds. The acceleration of the particle in the x-direction in feet per second squared is given by a, = 5.6t with t in seconds. When t = 0, y = 2.7 ft, x = 0, and v, = 0. The equation of the path of the particle can be written in the form (y - b)? = cx?. Find the constants b and c and calculate the magnitude of the velocity v of the particle for the instant when its x-coordinate reaches 20.4 ft. Answer: b = ft C = ft When x = 20.4 ft, v = ft/sec
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