A particle moves along the x axis from x; to xf. Of the following values of the initial and final coordinates, which results in a negative displacement? x = -4m, xf = 2m x₂ = -4m, f =-2 m ○ x₁ = 4m, f = 6 m x₂ = 8 m, f = 4 m x = -4m, f = 4 m none of these
A particle moves along the x axis from x; to xf. Of the following values of the initial and final coordinates, which results in a negative displacement? x = -4m, xf = 2m x₂ = -4m, f =-2 m ○ x₁ = 4m, f = 6 m x₂ = 8 m, f = 4 m x = -4m, f = 4 m none of these
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Question: Particle Movement and Displacement**
A particle moves along the x-axis from \( x_i \) to \( x_f \).
Of the following values of the initial and final coordinates, **which results in a negative displacement?**
- \( x_i = -4 \, m, \, x_f = 2 \, m \)
- \( x_i = -4 \, m, \, x_f = -2 \, m \)
- \( x_i = 4 \, m, \, x_f = 6 \, m \)
- \( x_i = 8 \, m, \, x_f = 4 \, m \)
- \( x_i = -4 \, m, \, x_f = 4 \, m \)
- \( \text{none of these} \)
*Note: Displacement is defined as the change in position of the particle, calculated as \( \Delta x = x_f - x_i \). A negative displacement indicates that the final position is less than the initial position.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F514923f2-e704-4cb3-8e16-d4c01e5e97ad%2Ff84146ed-3c6a-4653-9e3b-495f572b4ff9%2Ffl50wlg_processed.png&w=3840&q=75)
Transcribed Image Text:**Question: Particle Movement and Displacement**
A particle moves along the x-axis from \( x_i \) to \( x_f \).
Of the following values of the initial and final coordinates, **which results in a negative displacement?**
- \( x_i = -4 \, m, \, x_f = 2 \, m \)
- \( x_i = -4 \, m, \, x_f = -2 \, m \)
- \( x_i = 4 \, m, \, x_f = 6 \, m \)
- \( x_i = 8 \, m, \, x_f = 4 \, m \)
- \( x_i = -4 \, m, \, x_f = 4 \, m \)
- \( \text{none of these} \)
*Note: Displacement is defined as the change in position of the particle, calculated as \( \Delta x = x_f - x_i \). A negative displacement indicates that the final position is less than the initial position.*
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