y (m)3211x (m)2y² = 4-x34 A particle moves along a portion of the parabolic path y² = 4-x, where x and y are in meter, within thetime interval 0≤ t≤ 10 s. The horizontal component of the position of the particle is defined as x =4sin(t) where it is in second and is angle in radian. At the instant when t = 1.7288 s, calculate (a)the speed and (b) the magnitude of the normal acceleration of the particle. Hint (you may or may notuse this): The radius of curvature is expressed as:25³/2FOT+Р|d²y||dx²|

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