The figure gives the path of a squirrel moving about on level ground, from point A (at time t = 0), to points B (at t = 5 min), C (at t= 10 min), and finally D (at t = 15 min). Consider the average velocities of the squirrel from point A to each of the other three points. Ofthem, what are the (a) magnitude and (b) angle of the one with the least magnitude and (c) the magnitude and (d) angle of the one withthe greatest magnitude? Give the angles in the range (-180°, 180°]y (m)50250-25-5025CBD50x (m)

Name: The figure gives the path of a squirrel moving about on level ground,
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Description: The figure gives the path of a squirrel moving about on level ground, from point A (at time t = 0), to points B (at t = 5 min), C (at t= 10 min), and finally D (at t = 15 min). Consider the average velocities of the squirrel from point A to each of

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The figure gives the path of a squirrel moving about on level ground, from point A (at time t = 0), to points B (at t = 5 min), C (at t
= 10 min), and finally D (at t = 15 min). Consider the average velocities of the squirrel from point A to each of the other three points. Of
them, what are the (a) magnitude and (b) angle of the one with the least magnitude and (c) the magnitude and (d) angle of the one with
the greatest magnitude? Give the angles in the range (-180°, 180°]
y (m)
50
25
0
-25
-50
25
C
B
D
50
x (m)

Expert Solution

Step 1

To calculate the magnitude and direction of the lowest average velocity and the magnitude and direction of the highest average velocity.

Given:
The path of the squirrel:

The time taken to get to B: $t_{B} = 5 min = (5 \times 60) s$
The time taken to get to C: $t_{C} = 10 min = (10 \times 60) s$
The time taken to get to D: $t_{C} = 15 min = (15 \times 60) s$

To calculate:
(a) The magnitude of the least average velocity: $v_{l}$
(b) The angle of the least velocity: $θ_{l}$
(c) The magnitude of the highest average velocity: $v_{h}$
(d) The angle of the highest velocity: $θ_{h}$

The average velocity of a body is defined as the ratio of the displacement of the body to the time taken for the displacement.
$v = \frac{d}{t}$
The displacement of a body is defined as the shortest distance between the initial and the final position of the body. If the body moves in a cartesian coordinate system, then the displacement of the body is defines as:
$d = \sqrt{{(x_{f} - x_{i})}^{2} + {(y_{f} - y_{i})}^{2}}$
where,
$x_{i}, y_{i}$ are the x and y-coordinates of the initial position and
$x_{f}, y_{f}$ are the x and y-coordinates of the final position.

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