A particle moves along a horizontal line. Its position on the line in t seconds is given by s(t) = -t(t²-24t + 180). Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at t seconds, then their signs are given in the table below: t (0,6) 6 v(t) 0 a(t) + + + 0 1. From the 9th to the 11th second, when is the particle at its rightmost position? (6,8) 8 (8, 10) 10 (10, +00) + + + 0 - 1
A particle moves along a horizontal line. Its position on the line in t seconds is given by s(t) = -t(t²-24t + 180). Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at t seconds, then their signs are given in the table below: t (0,6) 6 v(t) 0 a(t) + + + 0 1. From the 9th to the 11th second, when is the particle at its rightmost position? (6,8) 8 (8, 10) 10 (10, +00) + + + 0 - 1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A particle moves along a horizontal line. Its position on the line in t seconds is given by
s(t) = -t(t²- 24t+ 180).
Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position
is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at
t seconds, then their signs are given in the table below:
(0,6) 6 (6,8)
(6,8)
t
v(t)
a(t)
1. From the 9th to the 11th second, when is the particle at its rightmost position?
+
0
+
+
8 (8, 10) 10 (10, +00)
+
0
+
+
0
-
-
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