A particle is moving in the xy plane starting from the origin with an initial velocity in x of 15 meters per second and an initial velocity in y of – 10 meters per second. The object moves at constant velocity in x and constant acceleration in y. The acceleration in y is -1 m/s. (a) Determine the total velocity vector ū; at any time, t. (Ans: v7 = 15i – (10 + t)j) (b) Determine the position of the particle 7 at any time, t. (Ans: 7 = (15t)i – (10t +t²)j) What is the position of the particle after 5 seconds? (Ans.:r = 97.63 m, 0 = 39.81) DIN

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A particle is moving in the xy plane starting from the origin with an initial velocity in x
of 15 meters per second and an initial velocity in y of – 10 meters per second. The object
moves at constant velocity in x and constant acceleration in y. The acceleration in y is
-1 m/s.
(a) Determine the total velocity vector v; at any time, t. (Ans.: = 15i – (10 + t)j)
(b) Determine the position of the particle ř at any time, t.
(Ans.: 7 = (15t)i – (10t +÷t²)j)
What is the position of the particle after 5 seconds? (Ans.: r = 97.63 m, 0 = 39.81°)
RIN
%3D
Transcribed Image Text:A particle is moving in the xy plane starting from the origin with an initial velocity in x of 15 meters per second and an initial velocity in y of – 10 meters per second. The object moves at constant velocity in x and constant acceleration in y. The acceleration in y is -1 m/s. (a) Determine the total velocity vector v; at any time, t. (Ans.: = 15i – (10 + t)j) (b) Determine the position of the particle ř at any time, t. (Ans.: 7 = (15t)i – (10t +÷t²)j) What is the position of the particle after 5 seconds? (Ans.: r = 97.63 m, 0 = 39.81°) RIN %3D
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