Suppose that an object's position vector as a function of time is given by r(t) = 15 cos(10.5 t) i + 15 sin(10.5 t) j  (m).  Calculate the magnitude of the particle's acceleration, in m/s2. (Please answer to the fourth decimal place - i.e 14.3225)

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Suppose that an object's position vector as a function of time is given by r(t) = 15 cos(10.5 t) i + 15 sin(10.5 t) j  (m).  Calculate the magnitude of the particle's acceleration, in m/s2.

(Please answer to the fourth decimal place - i.e 14.3225)

Expert Solution
Step 1

Given :

The function for the position of an object is,

rt=15cos10.5ti+15sin10.5tj

Step 2

The velocity v with which the object is moving is determined by,

Differentiating rt ,

velocity v=drdt

v=d15cos10.5ti+15sin10.5tjdt

v=(-10.5×15sin10.5t)i+(10.5×15cos10.5t)j

v=-157.5sin10.5ti+157.5cos10.5tj

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