At time t = 0, the position vector of a particle moving in the x-y plane is r = 4.62i m. By time t = 0.011 s, its position vector has become (4.84i + 0.54j) m. Determine the magnitude Vay of its average velocity during this interval and the angle made by the average velocity with the positive x-axis.
At time t = 0, the position vector of a particle moving in the x-y plane is r = 4.62i m. By time t = 0.011 s, its position vector has become (4.84i + 0.54j) m. Determine the magnitude Vay of its average velocity during this interval and the angle made by the average velocity with the positive x-axis.
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![At time t = 0, the position vector of a particle moving in the x-y plane is r = 4.62i m. By time t = 0.011 s, its position vector has become
(4.84i +0.54j) m. Determine the magnitude Vay of its average velocity during this interval and the angle 0 made by the average velocity
with the positive x-axis.
Answers:
Vav
0=
i
i
m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffbb784a1-d178-45b4-a0f0-c4e0e8e88c24%2Fbdcaa506-58df-4b2c-beaa-1943141109f9%2F58p8jql_processed.png&w=3840&q=75)
Transcribed Image Text:At time t = 0, the position vector of a particle moving in the x-y plane is r = 4.62i m. By time t = 0.011 s, its position vector has become
(4.84i +0.54j) m. Determine the magnitude Vay of its average velocity during this interval and the angle 0 made by the average velocity
with the positive x-axis.
Answers:
Vav
0=
i
i
m/s
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