A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect any effects due to air resistance.) Describe the velocity vector of the ball in terms of its x- and y-components, vx and vy, respectively, when it is 6.00 m above ground level and still moving upward. Ux = m/s V = Describe the velocity vector of the ball in terms of its magnitude v and angle € above the horizon when it is 6.00 m above ground level and still moving upward. Vy = m/s 0 = m/s

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Chapter1: Units, Trigonometry. And Vectors
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A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect
any effects due to air resistance.)
Describe the velocity vector of the ball in terms of its x- and y-components, vx and vy, respectively, when it is 6.00 m above
ground level and still moving upward.
Ux =
m/s
V =
Describe the velocity vector of the ball in terms of its magnitude v and angle € above the horizon when it is 6.00 m above
ground level and still moving upward.
Vy =
m/s
0 =
m/s
Transcribed Image Text:A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect any effects due to air resistance.) Describe the velocity vector of the ball in terms of its x- and y-components, vx and vy, respectively, when it is 6.00 m above ground level and still moving upward. Ux = m/s V = Describe the velocity vector of the ball in terms of its magnitude v and angle € above the horizon when it is 6.00 m above ground level and still moving upward. Vy = m/s 0 = m/s
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