An ion's position vector is initially 7 = (-3,9 m )i + (-8.6 m )j + (-3.4 m )k, and 9.3 s later it is 7 = (-2.6 m )i + (7.3 m )ĵ + (1.0 m )R. In unit-vector notation, what is its average velocity during the 9.3 s? Number i k Units m/s
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- The vertical displacement (in m) of a plane is 1.5 t2 up; t is the time (in s) after takeoff. The plane releases a package 2.0 s after takeoff. What is the magnitude of the velocity (in m/s) when the packaged is released? Report your answer in the appropriate number of significant digits. Answer valueIn reaching her destination, a backpacker walks with an average velocity of 1.14 m/s, due west. This average velocity results, because she hikes for 5.56 km with an average velocity of 3.44 m/s due west, turns around, and hikes with an average velocity of 0.376 m/s due east. How far east did she walk (in kilometers)? Vw dw VE West East de Number Units kmThe acceleration of a particle is given by a 4t - 37, where a is in meters per second squared and tis in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t = O is so = 9 m, and the initial velocity is vo = 0 m/s. After you have the general expressions, evaluate these expressions at the indicated times. Answers: m, v m/s Att- 2.9s. m. v- m/s Att 10.6 s, S-
- 10 t+ The x and y coordinates of an object moving in the xy plane are given by the following expressions x = 5 and y = - 4 t, where x is in meters and t is in seconds. The acceleration vector (in m/s) of the object at t = 4s is O a. 20 i - 32 j O b. - 8j O c. 20 i O d. - 32 jA person going for a walk follows the path shown in Figure P3.35. The total trip consists of four straight-line paths. At the end of the walk, what is the persons resultant displacement measured from the starting point? Figure P3.35A particle moves along two dimensions based on the following position vector r= [2.0 m + (3.00 m/s)f ]i + [(3.0 m)t - (2.00 m/s2)rlj a. Find the distance it covered in the first minute. b. Find the general expression of the instantaneous acceleration of the particle.
- We are standing on the top of a 1040 feet tall building and launch a small object upward. The object's height, measured in feet, after t seconds is h(t) = 16t? + 128t + 1040. A) What is the object initial velocity? ft/second B) What is the highest point that the object reaches? feetChapter 02, Problem 10 In reaching her destination, a backpacker walks with an average velocity of 1.26 m/s, due west. This average velocity results, because she hikes for 6.62 km with an average velocity of 2.54 m/s due west, turns around, and hikes with an average velocity of 0.381 m/s due east. How far east did she walk (in kilometers)? dw VE West East dɛ Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show WorkThe acceleration of a particle is given by a = 2t-20, where a is in meters per second squared and t is in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t = 0 is so = -5 m, and the initial velocity is vo = 6 m/s. Once you have determined the functions of time, answer the questions. Questions: When t = 5.1 s, S= V = a = Mi MI i m m/s m/s²
- EXE A bus makes a trip according to the position-time graph shown in the drawing. What is the average velocity (magnitude and direction) of the bus during (a) segment A. (b) segment B. and (c) segment C? Express your answers in km/h. 50.0 (A) Number (by Number Number Pater m | +40.0 +30.0 +200 +100 Units Units 05 10 15/ 2.05 26 Time (One of the fastest known animals is the Indian spine-tailed swift. A swift flies 2.80 km due north in a time of 32.8 s. a. What is its average velocity due north in meters per second? Enter a positive value if the average velocity is due north and enter a negative value if it is due south. answer in m/s b. What is its average velocity due north in miles per hour? Enter a positive value if the average velocity is due north and enter a negative value if it is due south. anser in mi/hThe acceleration of a particle is given by a 3t-37, where a is in meters per second squared and tis in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t=0 is so-8 m. and the initial velocity is vo-2 m/s. After you have the general expressions, evaluate these expressions at the indicated times. Answers: Att 5.5 s. 5 Att-10.5s, 5= m. v L m, m/s m/s