A parallel-plate capacitor of plate separation d is charged to a potential difference ΔV0. A dielectric slab of thickness d and dielectric constant k is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is UE /U0 = k. (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?
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A parallel-plate capacitor of plate separation d is charged to a potential difference ΔV0. A dielectric slab of thickness d and dielectric constant k is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is UE /U0 = k. (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?
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