A parallel plate capacitor filled with teflon (? = 2.1) has a capacitance of 6.5 A????1F. (A) If each plate has an area of 3.1 m^2 , what is distance between the plates? (B) Teflon has a breakdown field of 6.0 A????1x10^7 V/m. Determine the operating voltage of the capacitor, i.e. the maximum voltage at which the capacitor can operate. (C) How much energy is stored in the capacitor at its operating voltage? (D) What is the magnitude of the charge stored on each plate at the operating voltage?

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A parallel plate capacitor filled with teflon (? = 2.1) has a capacitance of 6.5 A????1F. (A) If each plate has an area of 3.1 m^2 , what is distance between the plates? (B) Teflon has a breakdown field of 6.0 A????1x10^7 V/m. Determine the operating voltage of the capacitor, i.e. the maximum voltage at which the capacitor can operate. (C) How much energy is stored in the capacitor at its operating voltage? (D) What is the magnitude of the charge stored on each plate at the operating voltage?

Expert Solution
Step 1

Given:

A parallel plate capacitor filled with Teflon = 2.1

Capacitance = 6.5 A

Area =3.1 m2

Formula used:

C=k0Ad

Step 2

A) On calculating the distance between plates,

C=k0Ad

On substituting the corresponding values,

d= 2.1×8.85×10-12×3.16.5×10-6=8.863×10-6 m =8.863 μm=0.008863 mm

Step 3

B) 

Vmax = Emax d

Vmax =6 x 107 x 8.863 x 10-6

On solving,

Vmax = 531.78 V

          

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