The plates of a parallel-plate capacitor areseparated by 0.12 mm.The permittivity of a vacuum is 8.85419 ×10-¹2 C²/N. m².If the space between the plates is air, whatplate area is required to provide a capacitanceof 9 pF?Answer in units of cm².

Given: The seperation between plates is 0.12 mm. The capacitance of the capacitor is 9 pF.

The plates of a parallel-plate capacitor are eparated by 0.12 mm. The permittivity of a vacuum is 8.85419 × 0-¹2 C²/N. m². If the space between the plates is air, what late area is required to provide a capacitance f 9 pF? Answer in units of cm².

The plates of a parallel-plate capacitor are eparated by 0.12 mm. The permittivity of a vacuum is 8.85419 × 0-¹2 C²/N. m². If the space between the plates is air, what late area is required to provide a capacitance f 9 pF? Answer in units of cm².

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter8: Capacitance

Section: Chapter Questions

Problem 61P: The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a...

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Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

The plates of a parallel-plate capacitor are
separated by 0.12 mm.
The permittivity of a vacuum is 8.85419 ×
10-¹2 C²/N. m².
If the space between the plates is air, what
plate area is required to provide a capacitance
of 9 pF?
Answer in units of cm².

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