The plates of a parallel-plate capacitor in vacuum are 3.70 mm apart and 2.75 m2 in area. When you apply a certain potential difference across the capacitor, the surface charge density on the positive plate is 1.40 * 10-5 C/m2. Calculate (a) the capacitance of the capacitor and (b) the potential difference.
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The plates of a parallel-plate capacitor in vacuum are
3.70 mm apart and 2.75 m2 in area. When you apply a certain potential
difference across the capacitor, the surface charge density on the
positive plate is 1.40 * 10-5 C/m2. Calculate (a) the capacitance of the
capacitor and (b) the potential difference.
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- Consider the Earth and a cloud layer 8.0 x 10 m above the planet to be the plates of a parallel-plate capacitor. (a) If the cloud layer has an area of 1.0 km² = 1.0 x 10° m2, what is the capacitance? (b) If an electric field strength greater than 3.0 x 10° N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold?An air-filled parallel-plate capacitor has plates of area 2.40 cm2 separated by 2.50 mm. The capacitor is connected to a 21.0-V battery. (a) Find the value of its capacitance. pF(b) What is the charge on the capacitor? pC(c) What is the magnitude of the uniform electric field between the plates?An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 1.80 mm. The capacitor is connected to a(n) 22.0 V battery. (a) Find the value of its capacitance. (b) What is the charge on the capacitor? (c) What is the magnitude of the uniform electric field between the plates?
- Regarding the Earth and a cloud layer 650 m above the Earth as the "plates" of a capacitor, calculate the capacitance if the cloud layer has an area of 1.53 km2. If an electric field of 2.0 × 106 N/C makes the air breakdown and conduct electricity (lightning), what is the maximum charge the cloud can hold? εo = 8.85 x 10−12 F/mA slab of copper of thickness b = 1.68 mm is thrust into a parallel-plate capacitor of plate area A = 1.96 cm2 and plate separation d = 5.35 mm, as shown in the figure; the slab is exactly halfway between the plates. (a) What is the capacitance after the slab is introduced? (b) If a charge q = 2.68 µC is maintained on the plates, what is the ratio of the stored energy before to that after the slab is inserted? (c) How much work is done on the slab as it is inserted? (d) Is the slab sucked in or must it be pushed in? Copper (a) Number 4.73e-13 Units (b) Number i 0.686 (c) Number i 5.36e-10 Units J (d) sucked inCapacitance Problem 18: A cylindrical capacitor is made of two concentric conducting cylinders. The inner cylinder has radius R1 = 19 cm and carries a uniform charge per unit length of λ = 30 μC/m. The outer cylinder has radius R2 = 45 cm and carries an equal but opposite charge distribution as the inner cylinder. Part (b) Calculate the electric potential difference between the outside and the inside cylinders in V. Part (c) Calculate the capacitance per unit length of these concentric cylinders in F/m.
- Consider a parallel-plate capacitor having an area of 2550 mm^2 and a plate separation of 4.9mm and with a material of dielectric constant 5.9 positioned between the plates. Also, the value of E0 is 8.85x10^-12F/m. a) What is the capacitance of this capacitor in pF? b) compute the electric field that must be applied for a charge pf 7.8x10^-8C to be stored on each plate in V/m.An electron is shot vertically upward through the tiny holes in the center of a parallel-plate capacitor. If the initial speed of the electron at the hole in the bottom plate of the capacitor is 4.00 x 106 m/s, what will be the speed of the electron just when it reaches the hole in the top plate? d = 2.00 cm, Q = 30.0 pC, A = area of either plate = 25.0 cm2, melectron = 9.109 x 10-31 kg, and qelectron = 1.602 x 10-19 CRegarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? C