A 197-V potential difference is applied across an air-filled parallel plate capacitor with a plate separation of 2.62 mm.(a) What is the strength of the electric field between the plates?E =kv/m(b) Calculate the surface charge density on the plates.μC/m²O(c) What is the area of the plates if the capacitance is 38.1 pF?A =1m²(d) What would the capacitance be if the plates had 5 times more area and were 2 times farther apart?pF

Given that Potential difference (∆V)=197 V. Seperation (d)=2.62 mm Capacitance (C) =38.1 pF

Answered: A 197-V potential difference is applied…

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