### Paired Difference Experiment AnalysisIn this example, a paired difference experiment is conducted, and the following data was collected:- Number of pairs (\(n_d\)): 16- Mean of the first sample (\(\bar{x}_1\)): 148- Mean of the second sample (\(\bar{x}_2\)): 155- Mean of the differences (\(\bar{x}_d\)): -7- Variance of the differences (\(s_d^2\)): 25#### ObjectiveThe objective is to determine the values of the t-statistic for which the null hypothesis \( \mu_1 - \mu_2 = 0 \) would be rejected in favor of the alternative hypothesis \( \mu_1 - \mu_2 < 0 \), using a significance level (\(\alpha\)) of 0.10.#### Steps and Options for Determining Rejection RegionsThe options provided for the rejection region are:**A.** The rejection region is \( t > \) [ ] **B.** The rejection region is \( t < \) [ ] or \( t > \) [ ] **C.** The rejection region is [ ] \( < t < \) [ ] **D.** The rejection region is \( t < \) [ ]### Explanation of Graphs or DiagramsIn the provided snippet, there are no graphs or diagrams included. The focus is on statistical hypothesis testing using the provided sample data and determining the rejection region for the t-statistic. To determine the specific values for the t-statistic and complete the options, one would generally follow these steps:1. **Calculate the test statistic:** This involves using the provided sample data to compute the test value.2. **Determine the critical value:** Based on the significance level (\(\alpha = 0.10\)) and the degrees of freedom (which is \( n_d - 1 \) for a paired t-test), the critical value for the t-distribution can be found using statistical tables or software.3. **Compare the test statistic to the critical value:** Decide which of the options matches the criterion for rejecting the null hypothesis.This example illustrates key concepts in hypothesis testing, particularly about paired difference experiments and the use of the t-distribution in making statistical decisions.

In order to determine whether the true difference between the means of population 1 and population 2…

A paired difference experiment produced the data given below. Complete parts a through e below. na = 16 Xq = - 7 s3 = 25 X1 = 148 X2 = 155 a. Determine the values of t for which the null hypothesis p, -42 = 0 would be rejected in favor of the alternative hypothesis u, - H2 <0. Use a= 0.10. (Round to two decimal places as needed.) O A. The rejection region is t> O B. The rejection region is t< or t>. O C. The rejection region is

A paired difference experiment produced the data given below. Complete parts a through e below. na = 16 Xq = - 7 s3 = 25 X1 = 148 X2 = 155 a. Determine the values of t for which the null hypothesis p, -42 = 0 would be rejected in favor of the alternative hypothesis u, - H2 <0. Use a= 0.10. (Round to two decimal places as needed.) O A. The rejection region is t> O B. The rejection region is t< or t>. O C. The rejection region is

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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please solve question 19 and 21
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14) part B
Question 10: give the conclusion.
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