A normally consolidated clay sample, which is fully saturated, was consolidated in thetriaxial cell under a particular all-round pressure of σ3. Upon consolidation, drainage valve isclosed and σ3 is kept constant while deviatoric stress was gradually increased under undrainedcondition until failure is reached. The following results are obtained:½ (σ1 – σ3) = 1/3 σ3 and ½ (σ1′ + σ3′) = 2/3 σ3a) Determine φ′,b) Express the pore pressure, uf, at failure in terms of cell pressure,c) Determine pore pressure coefficient Af′ at failured) Show that if sample is sheared under drained conditions, following results mayobtained: ½ (σ1 – σ3) = σ3 and ½ (σ1′ + σ3′) = 2σ3 5. A normally consolidated clay sample, which is fully saturated, was consolidated in thetriaxial cell under a particular all-round pressure of o3. Upon consolidation, drainage valve isclosed and o3 is kept constant while deviatoric stress was gradually increased under undrainedcondition until failure is reached. The following results are obtained:% (σι- σ ) - 13 σ and % (σ' + σ:) - 23 σa) Determine o',b) Express the pore pressure, uf, at failure in terms of cell pressure,c) Determine pore pressure coefficient Af at failured) Show that if sample is sheared under drained conditions, following results mayobtained: ½ (o1 – 03) = 03 and ½ (01'+ os') = 203

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Answered: A normally consolidated clay sample,…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A normally consolidated clay sample, which is fully saturated, was consolidated in the
triaxial cell under a particular all-round pressure of σ3. Upon consolidation, drainage valve is
closed and σ3 is kept constant while deviatoric stress was gradually increased under undrained
condition until failure is reached. The following results are obtained:

½ (σ1 – σ3) = 1/3 σ3 and ½ (σ1′ + σ3′) = 2/3 σ3
a) Determine φ′,
b) Express the pore pressure, uf, at failure in terms of cell pressure,
c) Determine pore pressure coefficient Af′ at failure
d) Show that if sample is sheared under drained conditions, following results may
obtained: ½ (σ1 – σ3) = σ3 and ½ (σ1′ + σ3′) = 2σ3

5. A normally consolidated clay sample, which is fully saturated, was consolidated in the
triaxial cell under a particular all-round pressure of o3. Upon consolidation, drainage valve is
closed and o3 is kept constant while deviatoric stress was gradually increased under undrained
condition until failure is reached. The following results are obtained:
% (σι- σ ) - 13 σ and % (σ' + σ:) - 23 σ
a) Determine o',
b) Express the pore pressure, uf, at failure in terms of cell pressure,
c) Determine pore pressure coefficient Af at failure
d) Show that if sample is sheared under drained conditions, following results may
obtained: ½ (o1 – 03) = 03 and ½ (01'+ os') = 203

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