Question 4<A normal distribution has a mean of 121 and a standard deviation of 6. Find the z-score for a data value of136.Question Help: VideoSubmit Question>Round to two decimal places

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Psychology students at a university completed the Dental Anxiety Scale questionnaire. Scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 11 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Anxiety Scale is normal with u = 11 and o = 3.5. Complete parts a through c. Click here to view a table of areas under the standardized normal curve. a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= 2 (Round to the nearest hundredth as needed.) b. Find the probability that someone scores between 10 and 15 on the Dental Anxiety Scale. P(10sxs 15) = (Round to four decimal places as needed.) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale. P(x> 17) =| (Round to four decimal places as needed.)
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The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
The ratings of applicants for credit are normally distributed with a mean of 200 and a standard deviation of 50. Find the 60th. percentile, the rating score that separates the lower 60% from the top 40%. Round to the nearest integer. a. 208 b. 187 c. 211 d. 213
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Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 70 105 The area of the shaded region is (Round to four decimal places as needed.)
Kirsten's quiz grade in her biology class is 63.5. If her class mean is 74 and the standard deviation is 7, what is Kirsten's Z-sore? -0.5 7 None of these
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Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. The area of the shaded region is (Round to four decimal places as needed.) 70 125 Q
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 120 The area of the shaded region is - (Round to four decimal places as needed.)

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A normal distribution has a mean of 121 and a standard deviation of 6. Find the z-score for a data value of 136. Question Help: Round to two decimal places Video