A nonuniform horizontal bar of mass m is supported by two massless wires against gravity. The left wire makes an angle a with the horizontal, and the right wire makes an angle B. The bar has length L. (Figure 1) Figure < 1 of 1 > Part A What is the position of the center of mass of the bar, measured as distance from the bar's left end? Express your answer in terms of a, B, and L. ▸ View Available Hint(s) [5] ΑΣΦ B α Submit ν Y Provide Feedback ग P 8 6 T DYN n Ф X y @ E x=L+ tan (a) tan (B) You have already submitted this answer. Enter a new answer. No credit lost. Try again. K Previous Answers Request Answer μ Next >

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement**

A nonuniform horizontal bar of mass \( m \) is supported by two massless wires against gravity. The left wire makes an angle \( \alpha \) with the horizontal, and the right wire makes an angle \( \beta \). The bar has length \( L \). (Figure 1)

**Task**

**Part A:**
What is the position of the center of mass of the bar, measured as distance \( x \) from the bar's left end? 

Express your answer in terms of \( \alpha \), \( \beta \), and \( L \).

*Equation to find:*
\[ x = L + \tan(\alpha) \tan(\beta) \]

**Instructions**

You have already submitted this answer. Enter a new answer. No credit lost. Try again.

---

**Figure Description**

The figure depicts a horizontal bar supported by two wires. 

- **Left Wire**: 
  - Makes an angle \( \alpha \) with the horizontal. 
  
- **Right Wire**:
  - Makes an angle \( \beta \) with the horizontal.

- **Bar**:
  - Length is denoted as \( L \).
  - The center of mass is indicated by a point labeled \( x \) along the bar.
Transcribed Image Text:**Problem Statement** A nonuniform horizontal bar of mass \( m \) is supported by two massless wires against gravity. The left wire makes an angle \( \alpha \) with the horizontal, and the right wire makes an angle \( \beta \). The bar has length \( L \). (Figure 1) **Task** **Part A:** What is the position of the center of mass of the bar, measured as distance \( x \) from the bar's left end? Express your answer in terms of \( \alpha \), \( \beta \), and \( L \). *Equation to find:* \[ x = L + \tan(\alpha) \tan(\beta) \] **Instructions** You have already submitted this answer. Enter a new answer. No credit lost. Try again. --- **Figure Description** The figure depicts a horizontal bar supported by two wires. - **Left Wire**: - Makes an angle \( \alpha \) with the horizontal. - **Right Wire**: - Makes an angle \( \beta \) with the horizontal. - **Bar**: - Length is denoted as \( L \). - The center of mass is indicated by a point labeled \( x \) along the bar.
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