A newspaper poll found that 52 percent of the respondents in a large random sample of likely voters in a districtintend to vote for candidate Smith rather than the opponent. A 95 percent confidence interval for the populationproportion was computed to be 0.52 ± 0.04. Based on the confidence interval, which of the following should thenewspaper report to its readers?(A) Smith will win because a majority of voters are in favor of Smith.(B) There is a 95% chance that Smith will win.(C) The poll predicts Smith will win, but there is a 5% chance that the prediction is incorrect due to samplingerror.(D) With 95% confidence, there is convincing evidence that Smith will win.(E) No prediction about who will win can be made with 95% confidence.
A newspaper poll found that 52 percent of the respondents in a large random sample of likely voters in a district
intend to vote for candidate Smith rather than the opponent. A 95 percent confidence interval for the population
proportion was computed to be 0.52 ± 0.04. Based on the confidence interval, which of the following should the
newspaper report to its readers?
(A) Smith will win because a majority of voters are in favor of Smith.
(B) There is a 95% chance that Smith will win.
(C) The poll predicts Smith will win, but there is a 5% chance that the prediction is incorrect due to sampling
error.
(D) With 95% confidence, there is convincing evidence that Smith will win.
(E) No prediction about who will win can be made with 95% confidence.
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