A new rocket launching system is considering short range launches. The existing system is p= 0.78 as the probability of a successful launch. A sample of 45 experimental launches is made with the new system. Construct a 95% confidence interval for p
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A new rocket launching system is considering short range launches. The existing system is p= 0.78 as the probability of a successful launch. A sample of 45 experimental launches is made with the new system. Construct a 95% confidence interval for p.
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- You randomly select a sample of n = 12. What is the appropriate value for t to compute a 99% confidence interval?Suppose a data set of 4,000 observations (n - 4,000) was analyzed using OLS to examine the factors influencing students' college grade point averages. The regression results are as follows, with standard errors in parentheses: colgpa-1.550 +0.0010 sat-0.03 hspere-0.05 hsize +-0.007 haize (0.00) (0.00006) (0.0007) (0.01) (0.000) where colgpa- GPA in college sat score on the SAT exam hspere -percentile in high school graduating class haize size of graduating class, in hundreds 11-4,000 R-0.254 R²-0.253 -0.45 The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school graduating class, is Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with aat 1,120, hapere 27, and haize 7. colga 1853+0.0010 sat (0,01) (0.0000) where colgpa-GPA in college sat0 sat-1,120 0.03 Asperc0-0.05 haize0+ 0.007 haize (0) (0000)A sample of freshman takes a reading comprehension test and their scores are summarized below. Sample scores: 16, 8, 8, 6, 9, 11, 13, 9, 10 a. if the mean for the general population on this test is m=12, can you conclude that this sample is significantly different from the population. Test with a=.05 b. Calculate a 90% confidence interval around your mean.
- IMR in Singapore. The infant mortality rate (IMR) is the number of infant deaths per 1000 live births. Suppose that you have been commissioned to estimate the IMR in Singapore. From a random sample of 1109 live births in Singapore, you find that 0.361% of them resulted in infant deaths. You next find a 90% confidence interval: or 0.000647 to 0.00657. You then conclude, “I can be 90% confident that the IMR in Singapore is somewhere between 0.647 and 6.57.” How did you do?A survey was conducted to determine what percentage of college seniors would have chosen to attend a differentcollege if they had known then what they know now. In a random sample of 100 seniors, 34 percent indicated thatthey would have attended a different college. A 90 percent confidence interval for the percentage of all seniors whowould have attended a different college isA simple random sample of 300 U.S. adults indicated that 11% approve of attempts to clone a human. Calculate a 95% confidence interval using the results of the survey.
- A retail store is considering adding a new product line to its inventory. The store wants to know whether the new product line will be popular with customers. To determine this, they take a random sample of customers and ask if they would be interested in buying the new product line. Of the 125 people they asked, 70 were interested in this new product line. The manager is interested in creating a 90 % confidence interval regarding the population parameter.A survey of 2450 golfers showed that 281 of them are left-handed. Construct a 90% confidence interval for the proportion of golfers that are left-handed. Question 10 options: (0.104, 0.125) (0.369, 0.451) (0.100, 0.130) (0.203, 0.293)A beverage company would like to determine if their drink is preferred to a rival company’s drink. They perform an experiment with 150 randomly selected individuals and have them taste test the two different drinks in a controlled environment so that each person's preference is independent of others. A 90% confidence interval for the proportion preferring their drink is (0.453, 0.587). Which of the following is the correct interpretation of this confidence interval? 90% of all consumers prefer this beverage company’s drink to their rival’s between 45.3% and 58.7% of the time. We’re 90% confident that between 45.3% and 58.7% of all consumers would prefer this beverage company’s drink to their rival’s drink. We’re 90% confident that there’s a 45.3% to 58.7% chance that a randomly selected person would prefer this beverage company’s drink to their rival’s drink. We’re 90% confident that the proportion of people in the sample who prefer this beverage company’s drink over their…
- In a study of treatments for very painful "cluster" headaches,... Find the 90% confidence interval using technology.When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted of 428 green peas and 152 yellow peas. 3. a. Find a 99% confidence interval estimate of the percentage of yellow peas.create a 90% confidence interval for the following data: x = 25 n = 100
