A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced energy levels of each oscillator are 5 × 10-21 J apart. Use k = 1.4 × 10-23 J/K. Part 1 (a) When the nanoparticle's energy is in the range 5 x 5x 10-21 J to 6 x 5x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i Save for Later K Using multiple attempts will impact your score. 40% score reduction after attempt 3 Attempts: 0 of 6 used Submit Answer Part 2 (b) When the nanoparticle's energy is in the range 8 x 5x 10 21 J to 9 x 5x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) Save for Later K Attempts: 0 of 6 used Submit Answer
A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced energy levels of each oscillator are 5 × 10-21 J apart. Use k = 1.4 × 10-23 J/K. Part 1 (a) When the nanoparticle's energy is in the range 5 x 5x 10-21 J to 6 x 5x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i Save for Later K Using multiple attempts will impact your score. 40% score reduction after attempt 3 Attempts: 0 of 6 used Submit Answer Part 2 (b) When the nanoparticle's energy is in the range 8 x 5x 10 21 J to 9 x 5x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) Save for Later K Attempts: 0 of 6 used Submit Answer
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![A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced
energy levels of each oscillator are 5 × 10-21 J apart. Use k = 1.4 × 10-23 J/K.
Part 1
(a) When the nanoparticle's energy is in the range 5 x 5x 10-21 J to 6 x 5x 10-21 J, what is the approximate temperature? (In order
to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)
i
Save for Later
K
Using multiple attempts will impact your score.
40% score reduction after attempt 3
Attempts: 0 of 6 used
Submit Answer
Part 2
(b) When the nanoparticle's energy is in the range 8 x 5x 10 21 J to 9 x 5x 10-21 J, what is the approximate temperature? (In order
to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)
Save for Later
K
Attempts: 0 of 6 used
Submit Answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee84687d-68cf-4a29-a35d-9391fdaee46e%2F1eee512b-9194-4364-9953-c250ddb4840d%2Frod428c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced
energy levels of each oscillator are 5 × 10-21 J apart. Use k = 1.4 × 10-23 J/K.
Part 1
(a) When the nanoparticle's energy is in the range 5 x 5x 10-21 J to 6 x 5x 10-21 J, what is the approximate temperature? (In order
to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)
i
Save for Later
K
Using multiple attempts will impact your score.
40% score reduction after attempt 3
Attempts: 0 of 6 used
Submit Answer
Part 2
(b) When the nanoparticle's energy is in the range 8 x 5x 10 21 J to 9 x 5x 10-21 J, what is the approximate temperature? (In order
to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)
Save for Later
K
Attempts: 0 of 6 used
Submit Answer
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