A municipal wastewater treatment plant (WWTP) receives a flow of 5.0 MGD. The WWTP does not have an equalization basin and therefore can have a peak hour flow that is 2.5 times the average daily flow. The WWTP has two circular, upflow clarifiers operating in parallel. The clarifiers must be designed to meet the following conditions: Average overflow rate = 1,000 gpd/ft (maximum) Peak overflow rate = 2,500 gpd/ft (maximum) Basin depth = 10 ft What is the diameter of each primary clarifier? Hint: calculate the diameter for each of the given conditions, and select your diameter based on your results. а.
A municipal wastewater treatment plant (WWTP) receives a flow of 5.0 MGD. The WWTP does not have an equalization basin and therefore can have a peak hour flow that is 2.5 times the average daily flow. The WWTP has two circular, upflow clarifiers operating in parallel. The clarifiers must be designed to meet the following conditions: Average overflow rate = 1,000 gpd/ft (maximum) Peak overflow rate = 2,500 gpd/ft (maximum) Basin depth = 10 ft What is the diameter of each primary clarifier? Hint: calculate the diameter for each of the given conditions, and select your diameter based on your results. а.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:b. What is the hydraulic residence time in each clarifier?
Transcribed Image Text:A municipal wastewater treatment plant (WWTP) receives a flow of 5.0 MGD. The WWTP
does not have an equalization basin and therefore can have a peak hour flow that is 2.5 times
the average daily flow. The WWTP has two circular, upflow clarifiers operating in parallel.
The clarifiers must be designed to meet the following conditions:
1,000 gpd/ft (maximum)
Average overflow rate =
Peak overflow rate = 2,500 gpd/ft° (maximum)
Basin depth = 10 ft
What is the diameter of each primary clarifier? Hint: calculate the diameter for each
a.
of the given conditions, and select your diameter based on your results.
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