A meterstick with a width of 0.03 m is rotated around the one of its ends. If a 0.20 kg spherical metal ball with 0.02 m radius is attached to the other opposite end, what is the moment of inertia and radius of gyration of the meterstick-ball set-up? Assume that the meterstick has negligible mass and thickness. Hint: Itotal = Irod + Isphere Irod =mrodw^2 - rotated at one end Isphere = Icenter of mass + msphere (w+r)^2 - using parallel-axis theorem Isphere = 2/5mspherer^2 + msphere (w+r)^2
A meterstick with a width of 0.03 m is rotated around the one of its ends. If a 0.20 kg spherical metal ball with 0.02 m radius is attached to the other opposite end, what is the moment of inertia and radius of gyration of the meterstick-ball set-up? Assume that the meterstick has negligible mass and thickness. Hint: Itotal = Irod + Isphere Irod =mrodw^2 - rotated at one end Isphere = Icenter of mass + msphere (w+r)^2 - using parallel-axis theorem Isphere = 2/5mspherer^2 + msphere (w+r)^2
Related questions
Question
A meterstick with a width of 0.03 m is rotated around the one of its ends. If a
0.20 kg spherical metal ball with 0.02 m radius is attached to the other opposite end, what is the moment of inertia and radius of gyration of the meterstick-ball set-up? Assume that the meterstick has negligible mass and thickness.
Hint:
Itotal = Irod + Isphere
Irod =mrodw^2 - rotated at one end
Isphere = Icenter of mass + msphere (w+r)^2 - using parallel-axis theorem
Isphere = 2/5mspherer^2 + msphere (w+r)^2
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
