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A long, thin rod (with uniformly distributed mass) rotates about an axis through its center. The rod has mass 8.kg and length 13.4.cm. Find the moment of inertia of the rod. 0.01261_kg-m? 0.01432 kg-m? С. A. D. 0.0132 kg-m? В. Е. 0.01389_kg-m? 0.01197_kg-m² F. 0.01139_kg-m²

A long, thin rod (with uniformly distributed mass) rotates about an axis through its center. The rod has mass 8.kg and length 13.4.cm. Find the moment of inertia of the rod. 0.01261_kg-m? 0.01432 kg-m? С. A. D. 0.0132 kg-m? В. Е. 0.01389_kg-m? 0.01197_kg-m² F. 0.01139_kg-m²

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A long, thin rod (with uniformly distributed mass) rotates about an axis through its center. The rod has mass 8.kg and length 13.4.cm. Find the moment of inertia of the rod. 0.01261_kg-m2 0.01432 kg-m2 0.01197 kg-m? D. 0.0132.kg-m? 0.01389_kg-m² 0.01139_kg•m² А. В. Е. С. F.
Transcribed Image Text:A long, thin rod (with uniformly distributed mass) rotates about an axis through its center. The rod has mass 8.kg and length 13.4.cm. Find the moment of inertia of the rod. 0.01261_kg-m2 0.01432 kg-m2 0.01197 kg-m? D. 0.0132.kg-m? 0.01389_kg-m² 0.01139_kg•m² А. В. Е. С. F.
Expert Solution
Step 1 Formula used

The moment of inertia of a rod rotating about an axis passing through its center is given by,

I = ML212

where M is the mass of the rod, and L is the length of the rod.

 

Step 2 Given

The mass of the rod is M = 8 kg

The length of the rod is L = 13.4 cm  = 0.134 m

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