A merry-go-round is a common piece of playground equipment. A 3.0-m-diameter merry-go-round, which can be modeled as a disk with a mass of 250 kg, is spinning at 25 rpm. John runs tangent to the merry-go-round at 4.6 m/s, in the same direction that it is turning, and jumps onto the outer edge. John's mass is 30 kg. Part A What is the merry-go-round's angular velocity, in rpm, after John jumps on? Express your answer in revolutions per minute to two significant figures. VE ΑΣΦ 1 W= 23 Submit In ? rpm

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# Physics Problem 12.81: Angular Velocity of a Merry-Go-Round

## Problem Description:

A merry-go-round is a common piece of playground equipment. A 3.0-meter-diameter merry-go-round, which can be modeled as a disk with a mass of 250 kg, is spinning at 25 revolutions per minute (rpm). John runs tangent to the merry-go-round at 4.6 meters per second (m/s), in the same direction that it is turning, and jumps onto the outer edge. John's mass is 30 kg.

### Part A:

**Question:**  
What is the merry-go-round's angular velocity, in rpm, after John jumps on? Express your answer in revolutions per minute to two significant figures.

**Answer Attempt:**  
Typed in: 23 rpm

**Feedback:**  
❌ Incorrect; Try Again, 5 attempts remaining

### Explanation:

You need to calculate the new angular velocity of the system after John jumps onto the merry-go-round. This involves applying the principle of conservation of angular momentum. The initial angular momentum of the system (merry-go-round + John) will equal the angular momentum after John jumps on.

#### Given Data:

- Diameter of the merry-go-round: 3.0 m
- Mass of the merry-go-round: 250 kg
- Initial angular velocity of the merry-go-round: 25 rpm
- Velocity of John: 4.6 m/s
- Mass of John: 30 kg

#### Required:

Calculate the new angular velocity in rpm.

**Considerations for Calculation:**

1. Determine the initial angular momentum of the merry-go-round.
2. Calculate the angular momentum contributed by John as he jumps onto the merry-go-round.
3. Apply the conservation of angular momentum to find the new angular velocity.

Use these considerations to arrive at a correct answer and try submitting again.
Transcribed Image Text:# Physics Problem 12.81: Angular Velocity of a Merry-Go-Round ## Problem Description: A merry-go-round is a common piece of playground equipment. A 3.0-meter-diameter merry-go-round, which can be modeled as a disk with a mass of 250 kg, is spinning at 25 revolutions per minute (rpm). John runs tangent to the merry-go-round at 4.6 meters per second (m/s), in the same direction that it is turning, and jumps onto the outer edge. John's mass is 30 kg. ### Part A: **Question:** What is the merry-go-round's angular velocity, in rpm, after John jumps on? Express your answer in revolutions per minute to two significant figures. **Answer Attempt:** Typed in: 23 rpm **Feedback:** ❌ Incorrect; Try Again, 5 attempts remaining ### Explanation: You need to calculate the new angular velocity of the system after John jumps onto the merry-go-round. This involves applying the principle of conservation of angular momentum. The initial angular momentum of the system (merry-go-round + John) will equal the angular momentum after John jumps on. #### Given Data: - Diameter of the merry-go-round: 3.0 m - Mass of the merry-go-round: 250 kg - Initial angular velocity of the merry-go-round: 25 rpm - Velocity of John: 4.6 m/s - Mass of John: 30 kg #### Required: Calculate the new angular velocity in rpm. **Considerations for Calculation:** 1. Determine the initial angular momentum of the merry-go-round. 2. Calculate the angular momentum contributed by John as he jumps onto the merry-go-round. 3. Apply the conservation of angular momentum to find the new angular velocity. Use these considerations to arrive at a correct answer and try submitting again.
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