A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 13 N · m. If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N) of the force she must exert on the wrench. 0.30 m 60 N

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 13 N · m. If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N) of the force she must exert on the wrench.

**Diagram Explanation:**

The diagram illustrates a wrench with a lever arm of 0.30 meters. The force \( \vec{F} \) is applied at a 60° angle to the lever arm. The task is to find the magnitude of force \( \vec{F} \) that results in a torque of 13 N · m.

**Key Details:**

- Torque required: 13 N · m
- Length of lever arm: 0.30 m
- Angle of applied force: 60°

\[ \text{Force ( } \vec{F} \text{) = } \underline{\hspace{3cm}} \text{ N} \]

Use the formula for torque: 
\[ \tau = r \times F \times \sin(\theta) \]

Where:
- \( \tau \) = torque 
- \( r \) = distance from pivot point (lever arm length)
- \( F \) = force
- \( \theta \) = angle between force and lever arm (60° in this case)
Transcribed Image Text:**Problem Statement:** A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 13 N · m. If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N) of the force she must exert on the wrench. **Diagram Explanation:** The diagram illustrates a wrench with a lever arm of 0.30 meters. The force \( \vec{F} \) is applied at a 60° angle to the lever arm. The task is to find the magnitude of force \( \vec{F} \) that results in a torque of 13 N · m. **Key Details:** - Torque required: 13 N · m - Length of lever arm: 0.30 m - Angle of applied force: 60° \[ \text{Force ( } \vec{F} \text{) = } \underline{\hspace{3cm}} \text{ N} \] Use the formula for torque: \[ \tau = r \times F \times \sin(\theta) \] Where: - \( \tau \) = torque - \( r \) = distance from pivot point (lever arm length) - \( F \) = force - \( \theta \) = angle between force and lever arm (60° in this case)
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