A mayor is concerned about the percentage of city residents who express disapproval of his job performance. His political committee pays for a newspaper ad, hoping to keep his disapproval rating below 21%. They will use a follow up poll to access effectiveness. What are the correct null and alternative hypotheses? Ho: p< .21 Ha: p= .21 Ho: p=.21 На: р > .21 Ho: p= .21 На: р< .21 Ho: p> .21 Ha: p= .21

A mayor is concerned about the percentage of city residents who express disapproval of his job performance. His political committee pays for a newspaper ad, hoping to keep his disapproval rating below 21%. They will use a follow up poll to access effectiveness. What are the correct null and alternative hypotheses? Ho: p< .21 Ha: p= .21 Ho: p=.21 На: р > .21 Ho: p= .21 На: р< .21 Ho: p> .21 Ha: p= .21

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

According to the Pew Research Center, 14% of adults rate basketball as their favorite sport. Your boss believes the proportion may be lower among adults over age 65, and wants you to collect evidence to see if this is true. You take a survey of adults over age 65, and only 12 out of 120 of them rate basketball as their favorite sport. You would like to set �=0.05. Your boss tells you that your firm will base some expensive decisions on the results of your hypothesis test, so a higher standard of evidence for rejecting the null hypothesis is needed. What should you do? Group of answer choices Keep the significance level the same but collect more data Increase the significance level to 10% Reduce the significance level to 1% Throw out observations that look suspicious thanks
USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1008 Chevrolet owners and found that 487 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use ? = 0.01. (a) What is the level of significance?State the null and alternate hypotheses. H0: p > 0.47; H1: p = 0.47H0: p = 0.47; H1: p ≠ 0.47 H0: p = 0.47; H1: p < 0.47H0: p = 0.47; H1: p > 0.47 (b) What sampling distribution will you use? The standard normal, since np < 5 and nq < 5.The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5.The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.)(c) Find the P-value of the test statistic. (Round your answer to four…
In 2013 students from a Statistics class at FSEV UK were asked to survey their friends who were 15-30 years old, in order to explore the interests of young people. The survey has a variety of questions, which are detailed in the Survey Key. For example, the column header “Music” is short for the question “I enjoy listening to music” and is rated 1-5, where 1 represents strongly disagree and 5 represents strongly agree. There is also some categorical data present as well. Survey participants record their gender, how often they smoke/drink, their internet usage, and education (just to name a few!). Please perform a hypothesis test based on one of the categorical variables and one survey question. For example, you could choose to prove the following: Survey participants who identify as an “only child” enjoy meeting new people (Survey score ). Here is an example: people who are right-handed (as identified in the data set) enjoy listening to music. Please be sure to use two columns…
Suppose 219 subjects are treated with a drug that is used to treat pain and 55 of them developed nausea. Use a 0.10 significance level to test the claim that more than 20% of users develop nausea.
Forbes reports that women in general trust recommendations from Pinterest more than recommendations from any other social network platform. But does trust in Pinterest differ by gender? The following sample data show the number of women and men who state in a recent survey that they trust recommendations made on Pinterest. Sample Trust recommendations made on Pinterest Women 150 117 Men 170 102 We want to determine whether trust in Pinterest differ by gender. Formulate the null and the alternative hypotheses. Use 1 to represent women and 2 to represent men. H0: Ha: Null: p1 – p2 ≥ 0; Alternative: p1 – p2 < 0 Null: p1 – p2 = 0 ; Alternative: p1 – p2 ≠ 0 Null: p1 – p2 ≤ 0; Alternative: p1 – p2 > 0 B. What the test statistics? You probably need to find the pooled proportion first. Pooled proportion is ___________. 0.6 0.78 0.6844 C. Test statistic is ________. 3.46 1.28 66.41 4.36
Suppose you want to find out how many people support Policy X. A standard polling approach is to just ask N many people whether or not they support Policy X, and take the fraction of people who say yes as an estimate of the probability that any one person supports the policy. Suppose that the probability someone supports the policy is p, which you do not know. Let îy be the number of people polled who supported the policy, divided by the total number of people polled N. However, a problem with polling is whether or not people are willing to answer honestly. If a question might be viewed as shameful or embarrassing (about politics, sexual activity, or whatever people are sensitive about), they may be reluctant to answer honestly. A potential solution to this is the following: suppose that 'YES' is the embarrassing or socially shameful answer; give the people you are polling the following instructions: flip a coin privately, and if it comes up heads answer honestly, but if it comes up…
There is some research to indicate that different dog breeds differ in emotionality. To consider these differences, a researcher administers a standard test of emotionality to 3 breeds of dogs (German Shepherd, Cocker Spaniel, and Chihuahua), with 4 dogs from each breed being tested. Higher scores mean higher emotionality. The results for the emotionality test scores appear below. Using the 7 steps of hypothesis testing, test the idea that there are differences in emotionality based on dog breed using α = .05 Emotionality Scores for Dogs German Shepherd Cocker Spaniel Chihuahua 6 0 10 1 4 12 7 0 9 2 0 8 T = 16 T = 4 T = 39 Gt = 59 N = 12 ∑x2 = 495 4. Decision Rule (Be sure to include your critical value) 5. Do your calculations 6. Make your decision 7. State your results in a sentence. Report your results in APA style including a measure of effect size. Be sure to include descriptive statistics (M). 8. Given your decision in #7, would…
A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
Management of a theater in a large city wants to know whether its popularity increased after it ran a popular musical. According to a previous study, 25% of city residents said they had been to the theater in the past year. A more recent study, conducted after the musical had run for a year, found that 156 of 536 residents sampled said they had been to the theater in the past year. Is there evidence at the ? = 0.05 level that the number of residents who have been to the theater has increased in the last year?
According to a book published in 2011, 45% of the undergraduate students in the United States show almost no gain in learning in their first two years of college (Richard Arum et al., Academically Adrift, University of Chicago Press, Chicago, 2011). A recent sample of 1540 undergraduate students showed that this percentage is 37%. Can you reject the null hypothesis at a 2.5% significance level in favor of the alternative that the percentage of undergraduate students in the United States who show almost no gain in learning in their first two years of college is currently lower than 45%. Use both the p-value and the critical-value approaches. Round your answers for the observed value of z and the critical value of z to two decimal places, and the p-value to four decimal places. Zobserved = p-value = Critical value = i Hence we can conclude that the percentage of undergraduate students in the U.S. who show almost no gain in learning in their fırst two years of college is currently 45%.
In 2010, shortly before a country's midterm elections, people in that country were dissatisfied with government and 57% of adults in the country thought that a third major party was needed. In a recent poll, 61% of 1067 adults in the country felt the same way. At the 20% significance level, do the data provide sufficient evidence to conclude that the percentage of all adults in the country who now think that a third major party is needed has changed from that in 2010? Use the one-proportion z-test to perform the appropriate hypothesis test.
The personality characteristics of business leaders (e.g., CEOS) are related to the operations of the businesses that they lead (Oreg & Berson, 2018). Traits like openness to experience are related to positive financial outcomes and other traits are related to negative financial outcomes for their businesses. Suppose that a board of directors is interested in evaluating the personality of their leadership. Among a sample of n = 16 managers, the sample mean of the openness to experiences dimension of personality was M = 4.50. Assuming that u = 4.24 and o = 1.05 (Cobb-Clark & Schurer, 2012), use a two-tailed hypothesis test with a = .05 to test the hypothesis that this company's business leaders' openness to experience is different from the population. Standard Normal Distribution Mean - 0.0 Standard Deviation 1.0 .7198 .1401 .1401 -3.0 -2.0 -1.0 0.0 1.0 2.0 3.0 -1.08 1.08 Step 1. Ho: ; H;: a = .05. Step 2. The critical region consists of Step 3. For these data the standard error is and…