A mass M = 1,6 kg is released from rest (Point 1), a distance 80 cm from a free spring (neither compressed, nor extended) of constant k = 570 N/m. The spring is compressed due to the impact of the mass M on a frictionless incline of 1 in 12. Analyse the Mass/Spring system on the inclined plane and calculate: • The angle to the horizontal 8 %3D The speed of the mass M when it just hits the free spring (Point 2) m/s The vanation of potential energy between points 1 and 2: A E, • The applicable variation in kinetic energy AEL
A mass M = 1,6 kg is released from rest (Point 1), a distance 80 cm from a free spring (neither compressed, nor extended) of constant k = 570 N/m. The spring is compressed due to the impact of the mass M on a frictionless incline of 1 in 12. Analyse the Mass/Spring system on the inclined plane and calculate: • The angle to the horizontal 8 %3D The speed of the mass M when it just hits the free spring (Point 2) m/s The vanation of potential energy between points 1 and 2: A E, • The applicable variation in kinetic energy AEL
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![The word variation, in this problem means change with applicable algebraic sign indicating an
increase or decrease of a quantity under observation.
ww
A mass M = 1.6 kg is released from rest (Point 1), a distance 80 cm from a free spring (neither
compressed, nor extended) of constant k = 570 N/m. The spring is compressed due to the impact of
the mass M on a frictionless incline of 1 in 12.
!!
Analyse the Mass/Spring system on the inclined plane and calculate:
• The angle to the horizontal 9 =
• The speed of the mass M when it just hits the free spring (Point 2]
m/3
The variation of potential energy between points 1 and 2: AE,
The applicable variation in kinetic energy AE
m
• The maximum compression of the spring (Point 3):
Considering the level of Point 3 as the reference height for the potential energy,
• The total variation of potential energy between 1 and 3 AE,
The total variation of kinetic between 1 and 3 AE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e70c558-a273-4fc6-a70b-0db03bbf08ce%2F7bfff680-452a-412b-9967-eff8500f017a%2Fauo5z8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The word variation, in this problem means change with applicable algebraic sign indicating an
increase or decrease of a quantity under observation.
ww
A mass M = 1.6 kg is released from rest (Point 1), a distance 80 cm from a free spring (neither
compressed, nor extended) of constant k = 570 N/m. The spring is compressed due to the impact of
the mass M on a frictionless incline of 1 in 12.
!!
Analyse the Mass/Spring system on the inclined plane and calculate:
• The angle to the horizontal 9 =
• The speed of the mass M when it just hits the free spring (Point 2]
m/3
The variation of potential energy between points 1 and 2: AE,
The applicable variation in kinetic energy AE
m
• The maximum compression of the spring (Point 3):
Considering the level of Point 3 as the reference height for the potential energy,
• The total variation of potential energy between 1 and 3 AE,
The total variation of kinetic between 1 and 3 AE
![12
T T2
T2
A horizantal shaft having a diameter of 100 mm.and a mass of 82 kg rotates in two bearings which are
4mfrom each other. A pulley on the shaft has a mass of 22 leg and is fixed a =1.2 m from the
bearing A. The total effective vertical downwards force in the belt drive of the pulley is due to tensions
T of magnitude 380 N defined with angle a 40° Illustrated in the figure and T, of magnitude 346
N defined by a2 =
%3D
= 450
Analyse tensionsT, and T in the vertical plane (u, z) and write the rectangular representations
T
3+
IN
+2
Te IN]
Assume a total effective vertical downwards force in the belt drive of the pulley 536 N and a coefficient
of friction of 2.98 between the shaft and the bearings and then calculate:
The support reactions at each bearing and the applicable frictional torque
• Bearing A RA
N with a frictional torque TorguA
Nm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e70c558-a273-4fc6-a70b-0db03bbf08ce%2F7bfff680-452a-412b-9967-eff8500f017a%2Fdyipgcf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12
T T2
T2
A horizantal shaft having a diameter of 100 mm.and a mass of 82 kg rotates in two bearings which are
4mfrom each other. A pulley on the shaft has a mass of 22 leg and is fixed a =1.2 m from the
bearing A. The total effective vertical downwards force in the belt drive of the pulley is due to tensions
T of magnitude 380 N defined with angle a 40° Illustrated in the figure and T, of magnitude 346
N defined by a2 =
%3D
= 450
Analyse tensionsT, and T in the vertical plane (u, z) and write the rectangular representations
T
3+
IN
+2
Te IN]
Assume a total effective vertical downwards force in the belt drive of the pulley 536 N and a coefficient
of friction of 2.98 between the shaft and the bearings and then calculate:
The support reactions at each bearing and the applicable frictional torque
• Bearing A RA
N with a frictional torque TorguA
Nm
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