A marketing research firm presented an advertisement for a product to random samples of potential customers inthree different regions of the country. The table below gives their reaction to the advertisement.REGIONIILiked576270Disliked312422Neutral121418The following is the R output:Pearson's Chi-squared testX-squared = 3.7043, df = *, p-value = 0.4475%3DIs there any evidence that the reaction to the advertisement is different for potential customers in the threeregions? (a = .05)The test problem ishedegree freedom isThe test statistic from the R output (keep 3 decimal points) isThe pvalue from the R output (keep 4 decimal points) isThe decision is

Solution-: We find the test of problem, degree of freedom, test statistic and p-value by using…

Answered: A marketing research firm presented an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Four Air Force trainee pilots take a test of visual acuity (higher scores mean better acuity) and an anxiety test (higher scores mean more anxiety. The scores are as follows: Person Acuity (x) Anxiety (y) 1 1 7 2 1 8 3 2 4 4 4 -1 Calculate critical value , SP the correlation coefficient and determine whether the correlation is statistically significant at the .05 significance level, two-tailed
A study compared tooth health and periodontal damage in a group of 40 young adult males with a tongue piercing and a control group of 50 young adult males without tongue piercing. Here are the summary statistics: Group Sample size Mean of enamel cracks StDev of enamel cracks Tongue piercing 40 4.1 3.7 No Tongue piercing 50 1.3 1.6 One question of interest was whether individuals with tongue piercing had more enamel cracks, on average. Is there evidence at 1% level that young adult males with a tongue piercing have significantly more enamel cracks than young adult males without a tongue piercing? Which method will you use to perform the test? Choose the correct one. 1-sample T test 2-sample T test 2-sample Z test. 2-proportion Z test Which distribution will you use here? If you use t distribution, give the degree of freedom. If you use z or normal, give the mean and standard deviation.
A study of emergency service facilities investigated the relationship between the number of facilities and the average distance traveled to provide the emergency service. The following table gives the data collected.
An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 51 42 Intermediate 55 43 Full-sized 62 47 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?ElectronicH0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?ElectronicH0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sizedH0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized Find the value of…
The leader of two postpartum women’s support groups is interested in the depression levels of the women in her groups. She administers the Center for Epidemiologic Studies Depression Scale (CES-D) screening test to the members of her groups. The CES-D is a 20-question self-test that measures depressive feelings and behaviors during the previous week. The mean depression level from the screening test for the 10 women in the first group is μ₁ = 16; the mean depression level for the 14 women in the second group is μ₂ = 10. Without calculating the weighted mean for the combined group, you know that the weighted mean is:
Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 356 of the 579 randomly selected wildfires looked at in the south were caused by humans while 322 of the 597 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for the difference between two population proportions b. The null and alternative hypotheses would be: Ho: p1 p2 v (please enter a decimal) H1: p1 V p2 v (Please enter a decimal) c. The test statistic z v = 2.620 (please show your answer to 3 decimal places.) d. The p-value = 0.0213 e. The p-value is >v a f. Based on this, we should reject g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) |the null hypothesis. O The results are statistically significant at a = 0.01, so there is sufficient evidence to conclude that the proportion of the 579…
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet) when stopping on a dry surface are shown in the table. Can you conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry surface? Use a =0.01. Welght, x Varlablity in braking distance, y 5960 5390 6500 5100 5870 4800 2 1.75 1.95 1.93 1.57 1.64 1.50 E Click here to view a table of critical values for Student's t-distribution. Setup the hypothesis for the test. Ho: P Vo Hạ: p Identify the critical value(s). Select the correct choice below and fill in any answer boxes within your choice. (Round to three decimal places as needed.) O A. The critical values are -to = and to = O B. The critical value is. Calculate the test statistic. t= (Round to three decimal places as needed.) What is your conclusion? a significant linear correlation between vehicle weight and variability in braking distance on a dry surface. There Venough evidence…
Pn.n.m.
AS RIC A researcher investigates on the effect of glutamates on the growth of Genovese basil plant. The data on the right are the records of basil (randomly selected) plant heights planted on soil with and without glutamate. At 5% level of Ric 1. BASIL PLANTS ON BASIL PLANTS ON SOIL WITHOUT SOIL WITH GLUTAMATES GLUTAMATES Height in centimeters Height in centimeters 16 18 19 18 23 29 25 12 25 24 21 21 26 23 18 significance, is there a significant difference between the heights of 20 20 24 21 17 24 19 24 19 Genovese basil plants grown on 20 23 soil with and without the presence 20 22 21 17 27 26 25 26 25 25 of glutamates? Assume that they standard 17 22 24 14 22 27 have deviations. unequal 19 23 20 24 12 22 22 14 26 15 18 24 25 24 23 18 15 20
Businesses know that customers often respond to background music. Do they also respond to odors? One study of this question took place in a small pizza restaurant in France on two Saturday evenings in May. On one of these evenings, a relaxing lavender odor was spread through the restaurant. On the other evening no scent was used. The data gives the time, in minutes, that two samples of 30 customers spent in the restaurant and the amount they spent in euros. No odor Lavender Minutes Euros spent Minutes Euros spent 103103 15.915.9 9292 21.921.9 6868 18.518.5 126126 18.518.5 7979 15.915.9 114114 22.322.3 106106 18.518.5 106106 21.921.9 7272 18.518.5 8989 18.518.5 121121 21.921.9 137137 24.924.9 9292 15.915.9 9393 18.518.5 8484 15.915.9 7676 22.522.5 7272 15.915.9 9898 21.521.5 9292 15.915.9 108108 21.921.9 8585 15.915.9 124124 21.521.5 6969 18.518.5 105105 18.518.5 7373 18.518.5 129129 25.525.5 8787 18.518.5 103103 18.518.5 109109 20.520.5 107107…
The General Social Survey (GSS) collects data on demographics, eduction and work, among many other characteristics of US residents. Suppose we want to estimate the difference between the average number of hours worked by all Americans with a college degree and those without a college degree. Is there sufficient evidence that there is a significant difference between the average number of hours worked by those Americans with a college degree vs. those Americans without a college degree? Use the following output: Welch Two Sample t-testdata: yes and not = 3.1181, df = 1098.5, p-value = 0.001867alternative hypothesis: true difference in means is not equal to 095 percent confidence interval: 1.011652 4.445822sample estimates:mean of x mean of y 42.81574 40.08701 Using the provided output, find the 95% confidence interval for the difference of the average amount of hours worked for those that have a college degree vs. those that do not have a college degree (ie: for the difference of two…

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