A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows. Hours of Training    Defects per Countertop 1    5 4    1 7    0 3    3 2    5 2    4 5    1 5    2 1    8 6    2 The estimated regression equation and the standard error are given.   Defects per Countertop=6.717822−1.004950(Hours of Training) Se=1.229787   Suppose a new employee has had 1 hour of training. What would be the 90% prediction interval for the number of defects per countertop? Round your answer to two decimal places.

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A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows.

Hours of Training    Defects per Countertop
1    5
4    1
7    0
3    3
2    5
2    4
5    1
5    2
1    8
6    2

The estimated regression equation and the standard error are given.
 

Defects per Countertop=6.717822−1.004950(Hours of Training)

Se=1.229787
 
Suppose a new employee has had 1 hour of training. What would be the 90% prediction interval for the number of defects per countertop? Round your answer to two decimal places.


 

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