A manufacturer produces lots of a canned food product. Let p denote the proportion of the lots that do not meet the product quality specifications. An n = 35, c = 0 acceptance sampling plan used. (a) Compute points on the operating characteristic curve when p = 0.01, 0.03, 0.10, and 0.20. (Round your answers to four decimal places.) p = 0.01 с 0 Probability of Accepting the Lo 24.6207 x the Lot (b) Plot the operating characteristic curve. 1.00 0.80+ 0.60+ 0.40+ 0.20- 0.00- p = 0.03 1.00 12.0525 x P = 0.10 0.8761 5 10 15 Percent Defective in the Lot 20 x p = 0.20 0.0142 Probability of Accepting the Lot 1.00 0.80+ 0.60- 0.40- 0.20+ 0.00 x 5 10 15 Percent Defective in the Lot € 20 Probability of Accepting the Lot 1.00 0.80 0.60- 0.40- 0.20- 0.00 5 10 15 Percent Defective in the Lot 20 @

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MS 3043(Online) HW Module: x +
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A manufacturer produces lots of a canned food product. Let p denote the proportion of the lots that do not meet the product quality specifications. An n = 35, c = 0 acceptance sampling plan will be
used.
(a) Compute points on the operating characteristic curve when p = 0.01, 0.03, 0.10, and 0.20. (Round your answers to four decimal places.)
хо
с
X
0
Probability of Accepting the Lot
(b) Plot the operating characteristic curve.
Probability of Accepting the Lot
24.6207 x
1.00
P = 0.01
0.80+
0.60+
0.40
0.20 +
0.00-
1.00
0.80-
0.60+
0.40
0.20-
0.00 +
P = 0.03
12.0525 X
P = 0.10
0.8761
5
10
15
Percent Defective in the Lot
5
10
15
Percent Defective in the Lot
20
20
x
P = 0.20
0.0142 x
Probability of Accepting the Lot
1.00
0.80-
0.60+
0.40-
0.20-
0.00
10
15
5
Percent Defective in the Lot
MacBook Pro
20
Probability of Accepting the Lot
1.00
0.80
0.60 +
0.40
0.20-
0.00-
5
10
15
Percent Defective in the Lot
20
Ⓡ
Transcribed Image Text:MS 3043(Online) HW Module: x + с webassign.net/web/Student/Assignment-Responses/submit?pos=4&dep=29026786&tags=autosave#question4759551_4 * 0 K Update A manufacturer produces lots of a canned food product. Let p denote the proportion of the lots that do not meet the product quality specifications. An n = 35, c = 0 acceptance sampling plan will be used. (a) Compute points on the operating characteristic curve when p = 0.01, 0.03, 0.10, and 0.20. (Round your answers to four decimal places.) хо с X 0 Probability of Accepting the Lot (b) Plot the operating characteristic curve. Probability of Accepting the Lot 24.6207 x 1.00 P = 0.01 0.80+ 0.60+ 0.40 0.20 + 0.00- 1.00 0.80- 0.60+ 0.40 0.20- 0.00 + P = 0.03 12.0525 X P = 0.10 0.8761 5 10 15 Percent Defective in the Lot 5 10 15 Percent Defective in the Lot 20 20 x P = 0.20 0.0142 x Probability of Accepting the Lot 1.00 0.80- 0.60+ 0.40- 0.20- 0.00 10 15 5 Percent Defective in the Lot MacBook Pro 20 Probability of Accepting the Lot 1.00 0.80 0.60 + 0.40 0.20- 0.00- 5 10 15 Percent Defective in the Lot 20 Ⓡ
←
MS 3043 (Online) HW Module X +
с
Tutorial
Probability of A
Probability of Accepting the Lot
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Submit Answer
0.40
0.20+
0.00-
1.00
0.80-
0.60-
0.40
0.20-
0.00 t
5
10
15
Percent Defective in the Lot
5
10
15
Percent Defective in the Lot
20
20
G
Probability of A
0.40
0.20-
0.00+
5
10
15
Percent Defective in the Lot
20
Probability of A
DO
0.40 +
0.20+
0.00 t
(c) What is the probability that the acceptance sampling plan will reject a lot containing 0.01 defective? (Round your answer to four decimal places.)
5
10
15
Percent Defective in the Lot
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Transcribed Image Text:← MS 3043 (Online) HW Module X + с Tutorial Probability of A Probability of Accepting the Lot webassign.net/web/Student/Assignment-Responses/submit?pos=4&dep=29026786&tags=autosave#question4759551_4 Submit Answer 0.40 0.20+ 0.00- 1.00 0.80- 0.60- 0.40 0.20- 0.00 t 5 10 15 Percent Defective in the Lot 5 10 15 Percent Defective in the Lot 20 20 G Probability of A 0.40 0.20- 0.00+ 5 10 15 Percent Defective in the Lot 20 Probability of A DO 0.40 + 0.20+ 0.00 t (c) What is the probability that the acceptance sampling plan will reject a lot containing 0.01 defective? (Round your answer to four decimal places.) 5 10 15 Percent Defective in the Lot View Previous Question Question 5 of 10 View Next Question * 0 K 20 Update
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