Measurements for the length and width of a rectangular plastic covers for CDs arerounded to the nearest mm (so they are discrete). Let X denote the length and Y denotethe width. The possible values of X are 129, 130, and 131 mm. The possible values of Yare 15 and 16 mm. The joint distribution is given by the following table:X=length| 129 130 131Y=width 15 0.12 0.42 0.0616 0.08 0.28 0.04The probability that a CD cover has width of 16 mm knowing that it has a length of 131mm is:0.20.4O 0.08O 0.13

The conditional probability of A given B is, P( A|B) = P( A n B) / P(B)

rounded to the nearest mm (so they are discrete). Let X denote the the width. The possible values of X are 129, 130, and 131 mm. Th are 15 and 16 mm. The joint distribution is given by the following X=length 129 130 131 Y=width 15 0.12 0.42 0.06 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that mm is: O 0.2 O 0.4 O 0.08

rounded to the nearest mm (so they are discrete). Let X denote the the width. The possible values of X are 129, 130, and 131 mm. Th are 15 and 16 mm. The joint distribution is given by the following X=length 129 130 131 Y=width 15 0.12 0.42 0.06 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that mm is: O 0.2 O 0.4 O 0.08

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Measurements for the length and width of a rectangular plastic covers for CDs are
rounded to the nearest mm (so they are discrete). Let X denote the length and Y denote
the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y
are 15 and 16 mm. The joint distribution is given by the following table:
X=length
| 129 130 131
Y=width 15 0.12 0.42 0.06
16 0.08 0.28 0.04
The probability that a CD cover has width of 16 mm knowing that it has a length of 131
mm is:
0.2
0.4
O 0.08
O 0.13

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