A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 14 kilograms. To test this claim, 49 pieces of each type of thread were tested under similar conditions. Type A thread had an average tensile strength of 82.7 kilograms with a standard deviation of 6.89 kilograms, while type B thread had an average tensile strength of 72.7 kilograms with a standard deviation of 6.25 kilograms. Test the manufacturer's claim using a 0.10 level of significance. Do not assume that the population variances are equal. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Let type A thread correspond to population 1 and let type B thread correspond to population 2. Identify the null and alternative hypotheses. Choose the correct answer below. O B. Ho: H1 - H2 = 14 H1: H1- 42 <14 OC. Ho: H1 - H2> 14 A. Ho: H1 - H2 = 14 H1: H1- H2> 14 H1: H1 -H2 = 14 O E. Ho: H1 - H2 = 14 OF. Ho: H1 - H2# 14 O D. Ho: H1 - H2< 14 H1: H1 - H2 = 14 H1: H1 - H2 # 14 H1: H1 - H2 = 14 Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to two decimal places as needed.) O A. t'> O B. t'< Oc. l< or t'>
A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 14 kilograms. To test this claim, 49 pieces of each type of thread were tested under similar conditions. Type A thread had an average tensile strength of 82.7 kilograms with a standard deviation of 6.89 kilograms, while type B thread had an average tensile strength of 72.7 kilograms with a standard deviation of 6.25 kilograms. Test the manufacturer's claim using a 0.10 level of significance. Do not assume that the population variances are equal. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Let type A thread correspond to population 1 and let type B thread correspond to population 2. Identify the null and alternative hypotheses. Choose the correct answer below. O B. Ho: H1 - H2 = 14 H1: H1- 42 <14 OC. Ho: H1 - H2> 14 A. Ho: H1 - H2 = 14 H1: H1- H2> 14 H1: H1 -H2 = 14 O E. Ho: H1 - H2 = 14 OF. Ho: H1 - H2# 14 O D. Ho: H1 - H2< 14 H1: H1 - H2 = 14 H1: H1 - H2 # 14 H1: H1 - H2 = 14 Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to two decimal places as needed.) O A. t'> O B. t'< Oc. l< or t'>
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Transcribed Image Text:A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 14 kilograms. To test this claim, 49 pieces of each type of thread
were tested under similar conditions. Type A thread had an average tensile strength of 82.7 kilograms with a standard deviation of 6.89 kilograms, while type B thread had an average tensile
strength of 72.7 kilograms with a standard deviation of 6.25 kilograms. Test the manufacturer's claim using a 0.10 level of significance. Do not assume that the population variances are equal.
Click here to view page 1 of the table of critical values of the t-distribution.
Click here to view page 2 of the table of critical values of the t-distribution.
Let type A thread correspond to population 1 and let type B thread correspond to population 2. ldentify the null and alternative hypotheses. Choose the correct answer below.
A. Ho: H1 - H2 = 14
B. Ho: H1 - H2 = 14
H1: 41 - H2 < 14
C. Ho: H1 - H2 > 14
H1: 41 - H2 = 14
%3D
%3D
O D. Ho: H1 -H2<14
H1: H1 - H2 = 14
E. Ho: H1 - H2 = 14
H1: H1 - 42# 14
O F. Ho: H1 - H2 # 14
H1: H1 - H2 = 14
Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice.
(Round to two decimal places as needed.)
O A. t'>
O B. t'<
Oc. t'<
or t' >
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