A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 13 kilograms. To test this claim, 51 pieces of each type of thread were tested under similar conditions. Type A thread had an average tensile strength of 89.8 kilograms with a standard deviation of 5.95 kilograms, while type B thread had an average tensile strength of 79.8 kilograms with a standard deviation of 5.37 kilograms. Test the manufacturer's claim using a 0.05 level of significance. Do not assume that the population variances are equal. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Let type A thread correspond to population 1 and let type B thread correspond to population 2. Identify the null and alternative hypotheses. Choose the correct answer below. A. Ho: H1 - H2 = 13 H1: H1- 42> 13 O B. Ho: H1 - H2 = 13 H1: H1-H2# 13 C. Ho: H1 - H2 > 13 D. Ho: H1 - H2 # 13 H1: H1 - H2 = 13 O F. Ho: H1 - H2 = 13 H1: H1- H2< 13 E. Ho: 41 - 42 <13 EL = Zr1 – H :H Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to two decimal places as needed.) O A. t'< O B. t'< or t'> Oc. t>

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A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at
least 13 kilograms. To test this claim, 51 pieces of each type of thread were tested under similar conditions. Type A thread
had an average tensile strength of 89.8 kilograms with a standard deviation of 5.95 kilograms, while type B thread had an
average tensile strength of 79.8 kilograms with a standard deviation of 5.37 kilograms. Test the manufacturer's claim using
a 0.05 level of significance. Do not assume that the population variances are equal.
Click here to view page 1 of the table of critical values of the t-distribution.
Click here to view page 2 of the table of critical values of the t-distribution.
Let type A thread correspond to population 1 and let type B thread correspond to population 2. Identify the null and
alternative hypotheses. Choose the correct answer below.
B. Ho: H1 - H2 = 13
Ho: H1 - H2 > 13
H1: H1 - H2 = 13
A. Ho: H1 - H2 = 13
%3D
H1: H1 - H2>13
H1: 41 - H2 # 13
D. Ho: H1 - H2 # 13
H1: H1- H2 = 13
E. Ho: H1 - H2 < 13
H1: H1- H2 = 13
F. Ho: H1 - H2 = 13
H1: H1 - H2 < 13
Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice.
(Round to two decimal places as needed.)
O A. t'<
В. t'<
or t'>
Oc. t'>
Transcribed Image Text:A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 13 kilograms. To test this claim, 51 pieces of each type of thread were tested under similar conditions. Type A thread had an average tensile strength of 89.8 kilograms with a standard deviation of 5.95 kilograms, while type B thread had an average tensile strength of 79.8 kilograms with a standard deviation of 5.37 kilograms. Test the manufacturer's claim using a 0.05 level of significance. Do not assume that the population variances are equal. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Let type A thread correspond to population 1 and let type B thread correspond to population 2. Identify the null and alternative hypotheses. Choose the correct answer below. B. Ho: H1 - H2 = 13 Ho: H1 - H2 > 13 H1: H1 - H2 = 13 A. Ho: H1 - H2 = 13 %3D H1: H1 - H2>13 H1: 41 - H2 # 13 D. Ho: H1 - H2 # 13 H1: H1- H2 = 13 E. Ho: H1 - H2 < 13 H1: H1- H2 = 13 F. Ho: H1 - H2 = 13 H1: H1 - H2 < 13 Identify the critical region. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to two decimal places as needed.) O A. t'< В. t'< or t'> Oc. t'>
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