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A magnetic circuit is given in the following figure, where Core: Area A, Permeability a N, turns N turns N turns • Cross-sectional area A. = 10 cm² ; • The air gap length g = 0.2 cm; • The number of turns of the winding N, = 100 and N = 50; • The permeability of the core is = 5004o, where Ho is the air permeability. • 4 = 0.8 cm; lz = 0.4 cm; l¼ = 4 cm; Neglect all the leakage and fringing flux components. 1). When the winding current is i, = 1 A and in = ip = 0 A, please calculate the flux density in the air gap. 2). When the winding current is i, = 1 A, iA = 14 , ip = -1 A, calculate the flux density in the air gap. 3). Please calculate the mutual inductance between the two windings carrying currents i, and ia; and the mutual inductance between the two windings carrying currents i, and ig.

A magnetic circuit is given in the following figure, where Core: Area A, Permeability a N, turns N turns N turns • Cross-sectional area A. = 10 cm² ; • The air gap length g = 0.2 cm; • The number of turns of the winding N, = 100 and N = 50; • The permeability of the core is = 5004o, where Ho is the air permeability. • 4 = 0.8 cm; lz = 0.4 cm; l¼ = 4 cm; Neglect all the leakage and fringing flux components. 1). When the winding current is i, = 1 A and in = ip = 0 A, please calculate the flux density in the air gap. 2). When the winding current is i, = 1 A, iA = 14 , ip = -1 A, calculate the flux density in the air gap. 3). Please calculate the mutual inductance between the two windings carrying currents i, and ia; and the mutual inductance between the two windings carrying currents i, and ig.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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A magnetic circuit is given in the following figure, where Core: Area A. Permeability u N, turns N turns N turns Cross-sectional area A, = 10 cm² ; The air gap length g = 0.2 cm; • The number of turns of the winding N, = 100 and N = 50; The permeability of the core is u = 5004o, where Ho is the air permeability. • 4 = 0.8 cm; lz = 0.4 cm; la = 4 cm; Neglect all the leakage and fringing flux components. 1). When the winding current is i, = 1 A and ia = ig = 0 A, please calculate the flux density in the air gap. 2). When the winding current is i, = 1 A, i, = 14 , ig = -1A, calculate the flux density in the air gap. 3). Please calculate the mutual inductance between the two windings carrying currents i, and i,; and the mutual inductance between the two windings carrying currents i, and ig.
Transcribed Image Text:A magnetic circuit is given in the following figure, where Core: Area A. Permeability u N, turns N turns N turns Cross-sectional area A, = 10 cm² ; The air gap length g = 0.2 cm; • The number of turns of the winding N, = 100 and N = 50; The permeability of the core is u = 5004o, where Ho is the air permeability. • 4 = 0.8 cm; lz = 0.4 cm; la = 4 cm; Neglect all the leakage and fringing flux components. 1). When the winding current is i, = 1 A and ia = ig = 0 A, please calculate the flux density in the air gap. 2). When the winding current is i, = 1 A, i, = 14 , ig = -1A, calculate the flux density in the air gap. 3). Please calculate the mutual inductance between the two windings carrying currents i, and i,; and the mutual inductance between the two windings carrying currents i, and ig.
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