A magnet in the form of a cylindrical rod has a length of 6.52 cm and a diameter of 1.43 cm. It has a uniform magnetization of 6.63 x 03 A/m. What is its magnetic dipole moment?
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- After being accelerated to a speed of 1.92×105 m/s , the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 34.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb.A charged particle is introduced into a uniform magnetic field Bz = 0.5 mTesla with an initial velocity vx = 1 x 106 m/s. It’s subsequent trajectory describes a circle with radius r = 2.4 cm. What is the specific charge q/m of this particle in terms of e/m = 1.67 x 1011C/kg? Select one: a. 3e/m b. e/2m c. e/3m d. 2e/mChapter 32, Problem 003 Your answer is partially correct. Try again. A Gaussian surface in the shape of a right circular cylinder with end caps has a radius of 15.0 cm and a length of 114 cm. Through one end there is an inward magnetic flux of 21.0 μwb. At the other end there is a uniform magnetic field of 1.27 mT, normal to the surface and directed outward. What are the (a) magnitude and (b) direction (inward or outward) of the net magnetic flux through the curved surface? (a) Number(6.871 (b)T inward the tolerance is +/-2%
- A positive oxygen-16 ion with a mass of 2.66 × 10-26 kg travels at 35 × 106 m/s perpendicular to a 2.50 T magnetic field, which makes it move in a circular path with a 0.332-m radius. Part (a) What is the charge of the ion, in coulombs? Part (b) What is the ratio of this charge to the magnitude of the electron’s charge?A small rod magnet has a magnetic field at a distance from it as large as Hom B = 2nz3 Where z is the distance from the magnet on the axis connecting the north pole and south, m is the moment of magnetic dipole. Assuming electrons orbit protons like small rod magnets, determine the m magnetic dipole of an electron orbiting an atom.i know the direction of the magnetic force on a proton is in the negative y direction and the direction of the magnetic force on an electron is in the positive y direction
- The magnetic dipole moment of the nickel atom is about 5.6 x 10-24 A· m2. (a) Calculate the maximum magnetic dipole moment (in A •m²) of a domain consisting of 1019 nickel atoms. A: m2 (b) What current (in A) would have to flow through a single circular loop of wire of diameter 2.2 cm to produce the magnetic dipole moment you calculated? AChapter 29, Problem 057 A student makes a short electromagnet by winding 430 turns of wire around a wooden cylinder of diameter d = 4.5 cm. The coil is connected to a battery producing a current of 3.1 A in the wire. (a) What is the magnitude of the magnetic dipole moment of this device? (b) At what axial distance z >> d will the magnetic field have the magnitude 7.0 µT (approximately one-tenth that of Earth's magnetic field)?The magnetic dipole moment of the cobalt atom is about 1.6 x 10-23 A · m². (a) Calculate the maximum magnetic dipole moment (in A •m²) of a domain consisting of 1020 cobalt atoms. A•m2 (b) What current (in A) would have to flow through a single circular loop of wire of diameter 2.6 cm to produce the magnetic dipole moment you calculated? A
- A 15 turn circular wire loop that lies in the xy-plane has a diameter of 0.30 m. A current of 1.5 A travels through the loop such that the current is in the clockwise direction when viewed from above the xy-plane. The loop is in a uniform magnetic field: B = +1.5 T j – 2.0T k. (a) What is the magnetic moment of the current loop? (b) What is the torque exerted on the loop by the magnetic field? (c) What is the potential (orientation) energy of the coil in this magnetic field? As usual, set the potential energy equal to zero when the magnetic moment is perpendicular to the magnetic field. For any vector quantities give the answer in unit-vector notation.Suppose that the magnetic dipole moment of Earth is 8.6 x 1025 J/T. (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? The radius of Earth is 6.37 x 106 m. Assume complete alignment of the dipoles. The density of Earth's inner core is 13 g/cm³. The magnetic dipole moment of an iron atom is 2.1 × 10-23 J/T. Iron has a molar mass of 55.9 g/mol. (Note: Earth's inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.) (a) Number i Units (b) Number i Units